I'm asking this again because i really am confused. Please help me.
1 answer:
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Answer:
Step-by-step explanation:
equation of a circle:
where (h, k) = center and r = radius
From inspection, we can see that the center of the circle = (0, 0)
and the radius = 1
Substitute into
and solve for
:
As point P is in quadrant 1, is positive, so
Answer:
Step-by-step explanation:
The given expression is x- = 2
and we have to solve this for the value of x,
( x- ) = (2)
x² - 15 = 2x
x² - 2x - 15 = 0
x² - 5x + 3x - 15 = 0
x ( x-5 ) + 3(x - 5) = 0
( x+3 )( x-5 ) = 0
( x+3) = 0
x = -3
or ( x- 5 ) = 0
x = 5
Therefore, x = -3 and 5 will be the solution.
Option E is the answer.