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tatiyna
3 years ago
12

Which types of heat transfer involve heat flow from hot objects to colder objects?

Physics
2 answers:
Makovka662 [10]3 years ago
5 0

Answer:

<u>convection, conduction, and radiation </u>

<u></u>

Explanation: Study Island

Lilit [14]3 years ago
3 0
Thermal radiation is a form of heat transfer<span> because the electromagnetic radiation emitted from the source carries energy away from the source to surrounding  </span><span>objects</span>
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Which changes would most likely limit the growth of a plant-eating animal population
BabaBlast [244]
Probably the changes in environment....
8 0
3 years ago
The "Garbage Project" at the University of Arizona reports that the amount of paper discarded by households per week is normally
Lorico [155]

Answer:

54%

Explanation:

We are given that

S.D=4.2 lb

Mean=\mu=9.4 lb

We have to find the percentage of household throw out at least 9 lb of paper  a week.

Normal distribution formula :

P(X\geq a)=P(z\geq \frac{a-\mu}{\sigma})

We have a=9

P(X\geq 9)=P(z\geq \frac{9-9.4}{4.2})=P(z\geq -0.1)

P(X\geq 9)=1-P(z

P(X\geq 9)=1-0.4602=0.5398\times 100=54%

Hence, the  percentage of household throw out at least of paper a week=54%

7 0
3 years ago
A proton with a speed of 3.000×105 m/s has a circular orbit just outside a uniformly charged sphere of radius 7.00 cm. What is t
Rama09 [41]

To solve this problem we will apply the principles of energy conservation. The kinetic energy in the object must be maintained and transformed into the potential electrostatic energy. Therefore mathematically

KE = PE

\frac{1}{2} mv^2 = \frac{kq_1q_2}{r}

Here,

m = mass (At this case of the proton)

v = Velocity

k = Coulomb's constant

q_{1,2} = Charge of each object

r= Distance between them

Rearranging to find the second charge we have that

q_2 = \frac{\frac{1}{2} mv^2 r}{kq_1}

Replacing,

q_2 = \frac{\frac{1}{2}(1.67*10^{-27})(3*10^5)^2(7*10^{-2})}{(9*10^9)(1.6*10^{-19})}

q_2 = 3.6531nC

Therefore the charge on the sphere is 3.6531nC

4 0
3 years ago
Two equipotential surfaces surround a +1.70 x 10-8-C point charge. How far is the 120-V surface from the 54.0-V surface?
UNO [17]

Answer:

1.55 m

Explanation:

The potential produced by a point charge, is inversely proportional to the distance from the charge to the point where the potential is being calculated, as follows:

V =\frac{k*q}{r}

As it only depends from the distance r, we can conclude that if the potential is the same for any point to a distance r from the point charge, the equipotencial surface must be a sphere of radius r.

Replacing q = +1.7*10⁻⁸ C, and k = 9*10⁹ N*m²/C², and V, by 120 V and 54 V, we can find the distance from the charge, to the points where we are calculating the potential V, as follows:

r1 =\frac{k*q}{V1} = \frac{9e9 N*m2/C2*1.7e-8C}{120 V} = 1.28 m

r2 =\frac{k*q}{V2} = \frac{9e9 N*m2/C2*1.7e-8C}{54V} = 2.83 m

The distance between both points, is just the difference between the radius of both spheres, as follows:

r₂ - r₁ = 1.55 m

5 0
3 years ago
As you run , your feet push on the ground with a force 500N . The ground pushes back on your feet with a force of 500N . (Please
Mademuasel [1]

Answer:

true

Explanation:

newtons third law says to every action there is always an equal and opposite reaction. so the answer is true

3 0
3 years ago
Read 2 more answers
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