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marshall27 [118]
3 years ago
7

Two poles are connected by a wire that is also connected to the ground. The first pole is 20ft tall and the second pole is 10ft

tall. There is a distance of 30ft between the two poles. Where should the wire be anchored to the ground to minimize the amount of wire needed

Physics
1 answer:
Natasha2012 [34]3 years ago
6 0

Answer: 31.6ft

Explanation:

Check the attachment for the diagram.

According to the right angle triangle AEC, we will use Pythagoras theorem to get |AC|. Note that |AE| = |AB| - |CD|

that is 20ft - 10ft = 10ft

According to the theorem, the square of the sum of the adjacent side and the opposite side is equal to the square of the hypotenuse.

|AE|^2 + |EC|^2 = |AC|^2

10^2 + 30^2 = |AC|^2

100 + 900 = |AC|^2

|AC| = √1000

|AC| = 31.6ft

Therefore, the wire should be anchored 31.6ft to the ground to minimize the amount of wire needed.

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Explanation:

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According to the Hooke’s law formula, the force is proportional to what measurement?
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Answer:

The small car and the truck experience the same average force.

Explanation:

Here we need to remember two of Newton's laws.

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And the third one says that;

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Well, this is explained by the second law.

Suppose that the mass of the car is m, and the mass of the truck is M.

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Then for the small car we have:

F = m*a

And for the truck:

F = M*a'

Because the force is the same for both of them, we can write:

m*a = M*a'

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y=v_0\sin20.0^\circ t+\dfrac12a_yt^2

The missile's final position after 9.20 s has to be a vector whose distance from the origin is 19,500 m and situated 32.0 deg relative the positive horizontal axis. This means the final position should have components

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\tan\theta=\dfrac{a_y}{a_x}\implies\theta=79.2^\circ

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