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alina1380 [7]
3 years ago
6

A 100 kg object and a 10 kg object are dropped simultaneously in a vacuum. Which of the following statements is true?

Physics
2 answers:
ella [17]3 years ago
7 0
In a vacuum, all objects fall at the same rate. Meaning that the 100 kg ball will fall at the same speed as the 10 kg ball. Assuming that both objects share the same starting acceleration, they will keep that acceleration until the fall is stopped.
In other words, your answer is the first one, Both objects will accelerate at 9.8 m/s
Zepler [3.9K]3 years ago
3 0

Answer:

Both objects will accelerate at 9.8 m/s².

Explanation:

According to given condition, a 100 kg object and a 10 kg object are dropped simultaneously in a vacuum. If there is no air resistance, when two objects of same or different masses will reach the ground at same time. The rate of descent does not depend on the amount of matter contained inside the object.

In the vacuum, no air resistance is present. Both of the objects will accelerate at 9.8 m/s² i.e. under the action of gravity.

So, the correct option is (a). Hence, this is the required solution.  

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For any given motion the velocity is
PtichkaEL [24]

Answer:

The velocity of an object refers to the rate at which the object's position changes. For any given motion, it is possible that an object could move very fast yet have an abnormally small

Formula:

velocity = distance travelled in a straight line/ time taken

       

8 0
3 years ago
a rectangular garden has a perimeter of 54 feet. it's length is 3 less than twice its width. write and solve an equation to solv
Yanka [14]
2(L+W)=54
L=2W-3
Substitute L in the first equation:
2((2W-3)+W)=54. 
Divide by 2:
(2W-3)+W=27
Simplify by collecting like terms:
3W-3=27. 
Add 3:
3W=30.
Divide by 3 to get that 
W=10. 
Substitute the L and W relations to get 
L=2W-3
L=2*10-3
L=17. 
The answers are length is 17 and width is 10.
5 0
3 years ago
Ammonia and _________ are waste products of animal cells. A. oxygen B. urine C. hydrogen D. carbon dioxide
pickupchik [31]

B or D, one of these are the correct answer

7 0
3 years ago
A ball whirls around in a vertical circle at the end of a string. The other end of the string is fixed at the center of the circ
AfilCa [17]

Answer:

a) Tb = m (g + vb² / R) , b)  Tt = m (g - vt² /R),    c) Tb = Ty + (vb² -vt²) /R

Explanation:

a) For this exercise we will use Newton's second law, at the bottom

       Tb - W = m a

Where the acceleration is centripetal

      a = v² / R

     Tb = W + m vb² / r

    Tb = m (g + vb² / R)

b) the tension at the top

     -Tt -w = m a

      Tt = W - m vt² / R

      Tt = m (g - vt² / R)

c) write the two equations and solve system

     Tb = m (g + vb² / R)

      Tt = m (g - vt² / R)            (-1)

We multiply by (1) and add

      Tb -Ty = vb² /R  -vt² /R

      Tb = Ty + (vb² -vt²) / R

6 0
4 years ago
What is the acceleration of an 800kg car that has a force of 2400N?<br> A= F/M
dangina [55]

You habe already the formula, what's wrong then? it's simple

A = F/M

A = 2400/800

A = 24/8

A = 3 m/s²

6 0
3 years ago
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