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alina1380 [7]
3 years ago
6

A 100 kg object and a 10 kg object are dropped simultaneously in a vacuum. Which of the following statements is true?

Physics
2 answers:
ella [17]3 years ago
7 0
In a vacuum, all objects fall at the same rate. Meaning that the 100 kg ball will fall at the same speed as the 10 kg ball. Assuming that both objects share the same starting acceleration, they will keep that acceleration until the fall is stopped.
In other words, your answer is the first one, Both objects will accelerate at 9.8 m/s
Zepler [3.9K]3 years ago
3 0

Answer:

Both objects will accelerate at 9.8 m/s².

Explanation:

According to given condition, a 100 kg object and a 10 kg object are dropped simultaneously in a vacuum. If there is no air resistance, when two objects of same or different masses will reach the ground at same time. The rate of descent does not depend on the amount of matter contained inside the object.

In the vacuum, no air resistance is present. Both of the objects will accelerate at 9.8 m/s² i.e. under the action of gravity.

So, the correct option is (a). Hence, this is the required solution.  

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Helium gas is compressed by an adiabatic compressor from an initial state of 14 psia and 50°F to a final temperature of 320°F in
iVinArrow [24]

Answer:

The value is  P_2 = 40.54 \ psla

Explanation:

From the question we are told that

 The initial pressure is  P_1 = 14\  psla

  The initial temperature is  T_1 =  50 \ F = (50 - 32) * [\frac{5}{9} ] + 273 = 283  \  K

   The final temperature is  T_2 =  320 \ F = (320 - 32) * [\frac{5}{9} ] + 273 =433  \  K

Generally the equation for adiabatic process is mathematically represented as

         PT^{\frac{\gamma}{1- \gamma} } =  Constant

=>      P_1T_1^{\frac{\gamma}{1- \gamma} } =  P_2T_2^{\frac{\gamma}{1- \gamma} }

Generally for a monoatomic gas  \gamma =  \frac{5}{3}

So

           14 * 283^{\frac{\frac{5}{3} }{1- [\frac{5}{3} ]} } =P_2 * 433^{\frac{\frac{5}{3} }{1- [\frac{5}{3} ]} }

=>       14 * 283^{-2.5} =P_2 * 433^{-2.5}

=>       P_2 = 40.54 \ psla

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Answer:

rotates faster

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Well, if the skydiver is at constant velocity, than there’s no acceleration, as stated by Newton’s first law. Thus the total net force would equate to 0. In order to make this statement true, the answer would have to be exactly 600 N.

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3 years ago
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