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goldfiish [28.3K]
4 years ago
12

Using the points B (4, -8) and C (-2,4) find the midpoint and distance

Mathematics
1 answer:
Elenna [48]4 years ago
5 0

Answer:

<h2> Mid point : </h2><h2 /><h2>( \frac{x_{1} +x_{2}}{2} ) , ( \frac{y_{1} +y_{2}}{2} )\\(\frac{4-2}{2}), (\frac{-8+4}{2})\\  (1,-2)</h2><h2>Distance</h2><h2>\sqrt{(x_{2}  -x_{1} )^{2}} +  \sqrt{(y_{2}  -y_{1} )^{2}}\\\sqrt{(-2  -4 )^{2}} +  \sqrt{(4  -(-8) )^{2}}\\\\\sqrt{36}+\sqrt{144}\\\\ 6+12\\ 18</h2>
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Which of the following are solutions to the equation below? Check all that apply. 9x^2-64=0
nikdorinn [45]

Answer:

E. -8/3

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Step-by-step explanation:

9x^2-64=0

Add 64 to each side

9x^2-64+64 = 0+64

9x^2 =64

Divide each side by 9

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Take the square root of each side

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We know that sqrt(a/b) = sqrt(a)/sqrt(b)

x = ±sqrt(64)/sqrt(9)

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A sociologist recorded the estimated life expectancies of women born in Center City. Use the data from women born in 1970 and 20
Veronika [31]

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So if we put the value x=1980 in the Y=0.213x-352  then

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Y=69.74

These values are closest to 70.1 whereas other options do not satisfy the condition.

Thus Y=0.213x-352  will represent this linear model shown in the data table.

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Step-by-step explanation:

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