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3 years ago

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A sound wave from a siren has an intensity of 111.2 W/m2 at a certain point, and a second sound wave from a nearby ambulance has

an intensity level 13 dB greater than the siren's sound wave at the same point. What is the intensity level of the sound wave due to the ambulance

1 answer:

Kazeer [188]3 years ago

5 0

Answer:

The intensity level of the sound wave due to the ambulance is 153.5 dB.

Explanation:

The intensity level of the sound wave due to the ambulance can be calculated using the following equation:

$\beta = 10log(\frac{I}{I_{0}})$

<u>Where</u>:

I: is the intensity of the sound wave from a siren = 111.2 W/m²

I₀: is the reference intensity = 1.0x10⁻¹² W/m²

$\beta = 10log(\frac{111.2 W/m^{2}}{1.0 \cdot 10^{-12} W/m^{2}}) = 140.5 dB$

Now, since the second sound wave from a nearby ambulance has an intensity level 13 dB we have:

$I_{a} = 13 dB + 140.5 dB = 153.5 dB$

Therefore, the intensity level of the sound wave due to the ambulance is 153.5 dB.

I hope it helps you!

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3 years ago

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