The power dissipated by the LED is 20 Watts and the work done for 1 hour 15 minutes is 56.25 kJ.
<h3>What is electrical power?</h3>
Electrical power is the rate at which electrical work is done.
- Electrical power = voltage × current
The LED is 75% efficient means that 75% of power dissipated by the LED is converted to light.
Total power dissipated = 5 × 2.5 = 12.5 Watts
- Work done = power × time (in seconds)
Work done = 12.5 × (1 × 3600 + 15 × 60)
Work done = 56250 J = 56.25 kJ
Therefore, the power dissipated by the LED is 20 Watts and the work done for 1 hour 15 minutes is 56.25 kJ.
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Answer:
Explanation:
maximum energy of capacitor
E = 1/2 C V ²
C is capacitance of capacitor and V is potential difference
given V = 88 V
E = 2002 x 10⁻⁶ J
Putting the values
2002 x 10⁻⁶ = 1/2 x C x 88²
C = .517 x 10⁻⁶ F .
In the second case
Energy E = 125 x 10⁻⁶ J .
C = .517 x 10⁻⁶
V = ?
E = 1/2 C V ²
125 x 10⁻⁶ = 1/2 x .517 x 10⁻⁶ x V²
V² = 483.55
V = 21.98 V .
Answer:
C
Explanation:
Glaciers break rocks because of the thawing and icing of water in rock crevices. These rocks get carried in the glacier. The glaciers move because the base of the glaciers melts ever so slightly due to the weight of the glacier above (pressure reduces the melting point of ice). This smoothens the slipping of the glaciers . When the glaciers get to a warmer place, it melts and the rocks in it are deposited.
