Answer: hello your question lacks some data hence I will be making an assumption to help resolve the problem within the scope of the question
answer:
≈ 95 units ( output level )
Step-by-step explanation:
Given data :
P = 2000 - Q/10
TC = 2Q^2 + 10Q + 200 ( assumed value )
<u>The output level where a purely monopolistic market will maximize profit</u>
<u>at MR = MC </u>
P = 2000 - Q/10 ------ ( 1 )
PQ = 2000Q - Q^2 / 10 ( aka TR )
MR = d (TR ) / dQ = 2000 - 2Q/10 = 2000 - Q/5
TC = 2Q^2 + 10Q + 200 ---- ( 2 )
MC = d (TC) / dQ = 4Q + 10
equating MR = MC
2000 - Q/5 = 4Q + 10
2000 - 10 = 4Q + Q/5
1990 = 20Q + Q
∴ Q = 1990 / 21 = 94.76 ≈ 95 units ( output level )
Answer:
C −2a^3+9a^2+45a+6ab^2+18b^2
Step-by-step explanation:
(a+3) ( −2a^2+15a+6b^2)
Distribute the a to the large term in parentheses and the 3 to the large term in parentheses
a ( −2a^2+15a+6b^2)+3 ( −2a^2+15a+6b^2)
−2a^3+15a^2+6ab^2 −6a^2+45a+18b^2
Combine like terms
−2a^3+15a^2−6a^2+6ab^2 +45a+18b^2
-2 a^3 + 9 a^2 + 6 a b^2 + 45 a + 18 b^2
The given problem describes a binomial distribution with p = 60% = 0.6. Given that there are 400 trials, i.e. n = 400.
a.) The mean is given by:

The standard deviation is given by:

b.) The mean means that in an experiment of 400 adult smokers, we expect on the average to get about 240 smokers who started smoking before turning 18 years.
c.) It would be unusual to observe <span>340 smokers who started smoking before turning 18 years old in a random sample of 400 adult smokers because 340 is far greater than the mean of the distribution.
340 is greater than 3 standard deviations from the mean of the distribution.</span>
True. According to the Commutative Property <span>of addition, the numbers could be put in any order and still result in the same answer. </span>
refection and translation i think
hdjdjsjsj I hope I got it right
I'm not sure if its a dilation if its getting smaller not bigger