Answer: y= -3x
(there is no y-intercept in the points you listed so if you can find one on a picture of your question, do so. but since i do not see a given y-intercept, i assume it is 0)
To find the slope, use the two points given.
1st: subtract the y-values. 0-6= -6.
2nd: subtract the x-values. 0-(-2)= 2
3rd: you have -6/2.
4th: simplify to get a slope of -3.
Answer:
The first listed equation is the correct equation to solve
The correct answer is: t = 5 seconds
Step-by-step explanation:
Let me mention first that there is an error in the statement that the gravitational pull of the Earth is 16 ft/s^2. It is in fact 32 ft/s^2, and the actual equation uses half of the acceleration multiplied by the square of the variable time, so it gives as final expression :

and we want to find the value/s for "t" that make this equation equal zero (when it reaches the ground and the object just touches the ground. This makes the equation we want to solve:

which solving for "t" becomes:

So we adopt the positive answer (positive time) since the negative value has no physical meaning for this problem.
That is: t = 5 seconds
Answer: OPTION C
Step-by-step explanation:
Remember that:
![\sqrt[n]{a^n}=a](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5En%7D%3Da)
And the Product of powers property establishes that:

Rewrite the expression:

Descompose 18 and 32 into their prime factors:

Substitute into the expression, then:

Finally,simplifying, you get:

The answer is B because thats the correct way to use a proper adjective