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serious [3.7K]
3 years ago
9

There are 7 cherries and 3 grapes in a bag. What is the pobability of selecting 2 grapes at random without replacement?

Mathematics
1 answer:
dlinn [17]3 years ago
3 0

Answer:

1/15

Step-by-step explanation:

7+3 = 10 items in the bag

P(grape) = grapes/total

                3/10

No replacement

7 cherries 2 grapes = 9 items

P(grape) =  grapes/total

                    2/9

P(grape, no replacement, grape) = 3/10*2/9

                                                       =1/15

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Answer:

You will need 18

Step-by-step explanation:

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2 years ago
Can u please help me with 27
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The answer would be 237.375. To get this answer, you will first use the formula given for each unit. First, you will do the first unit by putting 8 to the third power, or basically 8x8x8. After you get the product 512, you will then do the next unit. Do that one by doing 6.5 to the third power, or as followed, 6.5x6.5x6.5. Once you get the product 274.625, you will then subtract that from 512. You will then receive the answer 237.375.
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3 years ago
Please help me id you want BRIANLEIST!!! :)) ty!!!
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Answer:

5/3

Step-by-step explanation:

4 × x = (6×3+2)/3

---> 4x = 20/3

----> x = 20/12

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Hope it helps

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2 years ago
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3 years ago
7. License Plate Laws The Chapter Problem involved passenger cars in Connecticut and passenger cars in New York, but here we con
sergejj [24]

Yes it is true that commercial truck owners violate laws requiring front license plates at a higher rate than owners of passenger cars because null hypothesis is rejected.

Given among 2049 Connecticut passenger cars, 239 had only rear license plates. Among 334 Connecticut trucks, 45 had only rear license plates.

let p_{1} be the probability that commercial cars have rear license plates and p_{2} be the probability that connected trucks have rear license plates.

                         Cars                     Trucks                         Total

Total                  2049                    334                             2383

x                          239                      45                                284

p                        0.1166                   0.1347                          0.1191

α=0.05

Hypothesis will be  :

H_{0}:p_{1} =p_{2}

H_{1} :p_{1} < p_{2}

It is a left tailed test at 0.05 significance.

Standard errors of p=\sqrt{p(1-p)/n}

=\sqrt{(0.1191*0.8809)/2383}

=\sqrt{0.1049/2383}        

=0.0066

Test statistic Z=p difference/standard error

=(0.1166-0.1347)/0.0066

=-0.0181/0.0061

=-2.967

p value=0.001505<5%

Since p is less than 5% we reject null hypothesis.

We cannot calculate standard deviation so  we cannot calculate confidence interval.

Hence there is statistical evidence at 5% significance level to support that commercial truck owners violate laws requiring front license plates at a higher rate than owners of passenger cars.

Learn more about z test at brainly.com/question/14453510

#SPJ4

5 0
2 years ago
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