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serious [3.7K]
3 years ago
9

There are 7 cherries and 3 grapes in a bag. What is the pobability of selecting 2 grapes at random without replacement?

Mathematics
1 answer:
dlinn [17]3 years ago
3 0

Answer:

1/15

Step-by-step explanation:

7+3 = 10 items in the bag

P(grape) = grapes/total

                3/10

No replacement

7 cherries 2 grapes = 9 items

P(grape) =  grapes/total

                    2/9

P(grape, no replacement, grape) = 3/10*2/9

                                                       =1/15

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dedylja [7]

Answer:

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Step-by-step explanation:

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3 0
3 years ago
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hodyreva [135]

Answer:

Step-by-step explanation:

85 - 70 = 15

15/70 = 0.21428571428

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alina1380 [7]
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Sav [38]
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loris [4]

9514 1404 393

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