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3 years ago

There are 7 cherries and 3 grapes in a bag. What is the pobability of selecting 2 grapes at random without replacement?

Mathematics

1 answer:

dlinn [17]3 years ago

3 0

Answer:

1/15

Step-by-step explanation:

7+3 = 10 items in the bag

P(grape) = grapes/total

3/10

No replacement

7 cherries 2 grapes = 9 items

P(grape) = grapes/total

2/9

P(grape, no replacement, grape) = 3/10*2/9

=1/15

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Answer:

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Step-by-step explanation:

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$P=\frac{7}{578}= 0.01211$

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