u make 1.000 L of an aqueous solution that contains 35.0 g of sucrose (C12H22O11).Part AWhat is the molarity of sucrose in this
1 answer:
Answer:
0.102 M
Explanation:
Given data
- Mass of sucrose (solute): 35.0 g
- Volume of solution: 1.000 L
Step 1: Calculate the moles of solute
The molar mass of sucrose is 342.3 g/mol. The moles corresponding to 35.0 g of sucrose are:
Step 2: Calculate the molarity of sucrose in the solution
The molarity is equal to the moles of solute divided by the liters of solution.
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Answer:
Explanation:
Given that:-
Pressure =
The expression for the conversion of pressure in Pascal to pressure in atm is shown below:
P (Pa) = P (atm)
Given the value of pressure = 43,836 Pa
So,
=
atm
Pressure = 6.80977 atm
Volume = = 2.3 L ( 1 m³ = 1000 L)
n = 2 mol
Using ideal gas equation as:
PV=nRT
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L.atm/K.mol
Applying the equation as:
6.80977 atm × 2.3 L = 2 mol × 0.0821 L.atm/K.mol × T
⇒T = 95.39 K
The expression for the kinetic energy is:-
k is Boltzmann's constant =
T is the temperature
So,