Question

u make 1.000 L of an aqueous solution that contains 35.0 g of sucrose (C12H22O11).Part AWhat is the molarity of sucrose in this solution?Express your answer to three significant figures.M

Answer 1

Answer:

0.102 M

Explanation:

Given data

• Mass of sucrose (solute): 35.0 g

• Volume of solution: 1.000 L

Step 1: Calculate the moles of solute

The molar mass of sucrose is 342.3 g/mol. The moles corresponding to 35.0 g of sucrose are:

$35.0g \times \frac{1mol}{342.3g} =0.102mol$

Step 2: Calculate the molarity of sucrose in the solution

The molarity is equal to the moles of solute divided by the liters of solution.

$M=\frac{0.102mol}{1.000L} =0.102 M$