0.3 L is the final volume when M₁ = 3 M, V₁ = 0.125L, M₂ = 1.25M.
<h3>What is volume?</h3>
The amount of space occupied by a three-dimensional figure as measured in cubic units.
Given data:
M₁ = 3 M
V₁ = 0.125L
M₂ = 1.25M
V₂ = ?
Solution:
M₁V₁ = M₂V₂
3 M × 0.125L = 1.25M × V₂
V₂ = 0.3 L
Hence, 0.3 L is the final volume.
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Answer:
13.26 g has 4 significant figures
First, we'll balance the equation
C3H8 + 5O2 --> 3CO2 + 4H2O
Next, we know that a gas at stp occupies 22.4 liters/mole, so we can find the number of moles of oxygen gas.
15 liters O2 * (1 mole O2)/(22.4 liters O2) = 0.67 moles O2
Now we know from our balanced equation that there are 3 moles of CO2 per mole of O2, so we can find the number of moles of CO2 we produce.
0.67 moles O2 * (3 moles CO2/5 moles O2) = 0.40 moles CO2
Now, we have the number of moles of CO2, and we know that one mole occupies 22.4 liters, we can find the number of liters
.40 moles CO2 * (22.4 liters CO2)/(1 mole CO2) = 9.0 liters of CO2
The answer is D
It is important to test only one variable, because 2 or more may cause changes in the original variable that weren't supposed to occur
Answer:
20.446cm3
Explanation:
The following were obtained from the question given:
V1 (initial volume) = 24.568 cm3
T1 (initial temperature) = 25°C = 25 + 273 = 298K
T2 (final temperature) = - 25°C = - 25 + 273 = 248K
V2 (final volume) = ?
Since the pressure is constant, the gas is obeying Charles' law. With the Charles' law equation V1/T1 = V2/T2, we can easily calculate the final volume as follow:
V1/T1 = V2/T2
24.568/298 = V2/248
Cross multiply to express in linear form as shown below:
298 x V2 = 24.568 x 248
Divide both side by 298
V2 = (24.568 x 248) /298
V2 = 20.446cm3
From the calculations made above, the volume of the gas at -25°C is 20.446cm3
