The volume of H₂ : = 15.2208 L
<h3>Further explanation</h3>
Given
Reaction
2 As (s) + 6 NaOH (aq) → 2 Na₃AsO₃ (s) + 3 H₂ (g)
34.0g of As
Required
The volume of H₂ at STP
Solution
mol As (Ar = 75 g/mol) :
= mass : Ar
= 34 g : 75 g/mol
= 0.453 mol
From the equation, mol ratio As : H₂ = 2 : 3, so mol H₂ :
=3/2 x mol As
=3/2 x 0.453
= 0.6795
At STP, 1 mol = 22.4 L, so :
= 0.6795 x 22.4 L
= 15.2208 L
B. They work against a strong gravitational force
Hey there!
325 mL in liters:
325 / 1000 => 0.325 L
1 mole ( Ne ) ------------- 22.4 L ( at STP )
moles ( Ne ) ------------ 0.325 L
moles Ne = 0.325 * 1 / 22.4
moles Ne = 0.325 / 22.4
moles Ne = 0.0145 moles
hope this helps!
Answer:
<h3>The answer is 0.622 mL</h3>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula
From the question
mass = 12 g
density = 19.30 g/mL
We have
We have the final answer as
<h3>0.622 mL</h3>
Hope this helps you
Opp that that person has to correct answer
