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VashaNatasha [74]
3 years ago
15

How do you solve this someone help please

Mathematics
1 answer:
tekilochka [14]3 years ago
5 0
The film lasted until 8:27.

This is true because 102 minutes is 1 hour and 42 minutes. If you add 1 hour and 42 minutes onto 6 hours and 45 minutes, the beginning time then. You would get 8 hours and 27 minutes.

This is my equation. ---->
  6:45
+1:42
_____
   7:87 <---- But that isn't correct because 87 minutes is over an hour.  

So if you do the correct numbers you would get 8:27 as your answer! 

HOPE I HELPED!!! :D
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u= -449

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SCALCET8 3.8.001.MI. A population of protozoa develops with a constant relative growth rate of 0.6137 per member per day. On day
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Is there supposed to be a picture?

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Which drawing shows two lines that intersect at Point a ax, tab, two lines ab, straight x a.​
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The drawing which shows two lines that intersect at Point, A is as represented in Choice 1: Top-left corner.

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Question 2b only! Evaluate using the definition of the definite integral(that means using the limit of a Riemann sum
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Hello,

Step-by-step explanation:

We divide the interval [a b] in n equal parts.

\Delta x=\dfrac{b-a}{n} \\\\x_i=a+\Delta x *i \ for\ i=1\ to\ n\\\\y_i=x_i^2=(a+\Delta x *i)^2=a^2+(\Delta x *i)^2+2*a*\Delta x *i\\\\\\Area\ of\ i^{th} \ rectangle=R(x_i)=\Delta x * y_i\\

\displaystyle \sum_{i=1}^{n} R(x_i)=\dfrac{b-a}{n}*\sum_{i=1}^{n}\  (a^2 +(\dfrac{b-a}{n})^2*i^2+2*a*\dfrac{b-a}{n}*i)\\

=(b-a)^2*a^2+(\dfrac{b-a}{n})^3*\dfrac{n(n+1)(2n+1)}{6} +2*a*(\dfrac{b-a}{n})^2*\dfrac{n (n+1)} {2} \\\\\displaystyle \int\limits^a_b {x^2} \, dx = \lim_{n \to \infty} \sum_{i=1}^{n} R(x_i)\\\\=(b-a)*a^2+\dfrac{(b-a)^3 }{3} +a(b-a)^2\\\\=a^2b-a^3+\dfrac{1}{3} (b^3-3ab^2+3a^2b-a^3)+a^3+ab^2-2a^2b\\\\=\dfrac{b^3}{3}-ab^2+ab^2+a^2b+a^2b-2a^2b-\dfrac{a^3}{3}  \\\\\\\boxed{\int\limits^a_b {x^2} \, dx =\dfrac{b^3}{3} -\dfrac{a^3}{3}}\\

4 0
2 years ago
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