Answer:
Step-by-step explanation:
y = sin(t^2)
y' = 2tcos(t^2)
y'' = 2cos(t^2) - 4t^2sin(t^2)
so the equation become
2cos(t^2) - 4t^2sin(t^2) + p(t)(2tcos(t^2)) + q(t)sin(t^2) = 0
when t=0, above eqution is 2. That is, there does not exist the solution. so y can not be a solution on I containing t=0.
Answer:
There are no like terms.
Step-by-step explanation:
basically that is your answer you can not solve so it will be 3ax – 3ay – 2bx + 2by
Answer:
The factored form is (sin x +2)(sin x-1)
Step-by-step explanation:
We have been given the trigonometric function 
We can factor this by AC method. In AC method we multiply the term a and c and then write the middle term b in such a way that the sum/difference is equal to the product 'ac'
Using the method, we can write sinx as 2sinx -sinx

Now, we group the first two terms and the last two terms

Now, we take GCF from each group

Factor out (sinx+2)

Therefore, the factored form is (sin x +2)(sin x-1)
Answer:
The answer to this would be .8
Step-by-step explanation:
A tenth is only one figure, and due to the rule of "5 and above give it a shove; 4 and below let it go", this number would round to 0.8.