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3 years ago

What statement BEST explains why the specific heat of water is higher than the specific heat of most other substances?

1 answer:

8 0

For the answer to the question above, Due to water's polarity, water can absorb heat without a significant temperature change. The specific heat of liquid water is 4.183 J / g K
I hope my answer helped you with your problem. Have a nice day!

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During a group project, two students constructed a simple machine to add to their Rube Goldberg project. They were told to creat

Zinaida [17]

Answer:

Image B

Explanation:

although I'm not exactly sure, i've recently gotten this question as well. but model B demonstrates the force- distance trade off because you can see how in that image them distance is increased in the force is decreased with the object being shorter. hopefully this helps in some way

4 0

3 years ago

Read 2 more answers

An 12 N force is applied to a 1 kg object. What is the magnitude of the objects acceleration?

Sauron [17]

Answer:

a=12 m/s²

Explanation:

Newton's second law of motion states that the acceleration of a body is directly proportional to the force applied and takes place in the direction of force.

This can be summarized as: F=ma, where m is the mass of the object on which force F acts. a is the acceleration due to the force applied.

12N= 1kg×a

a=12N/1kg

a=12m/s²

6 0

4 years ago

A 0.500-kg mass suspended from a spring oscillates with a period of 1.18 s. How much mass must be added to the object to change

olga55 [171]

Answer:

The add mass = 5.465 kg

Explanation:

Note: Since the spring is the same, the length and Tension are constant.

f ∝ √(1/m)........................ Equation 1 (length and Tension are constant.)

Where f = frequency, m = mass of the spring.

But f = 1/T ..................... Equation 2

Substituting Equation 2 into equation 1.

1/T ∝ √(1/m)

Therefore,

T ∝ √(m)

Therefore,

T₁/√m₁ = k

where k = Constant of proportionality.

T₁/√m₁ = T₂/√m₂ ........................ Equation 3

making m₂ the subject of the equation

m₂ = T₂²(m₁)/T₁²........................... Equation 4

Where T₁ = initial, m₁ = initial mass, T₂ = final period, m₂ = final mass.

Given: T₁ = 1.18 s m₁ = 0.50 kg, T₂ = 2.07 s.

Substituting into equation 4

m₂ = (2.07)²(0.5)/(1.18)²

m₂ = 4.285(1.392)

m₂ = 5.965 kg.

Added mass = m₂ - m₁

Added mass = 5.965 - 0.5

Added mass = 5.465 kg.

Thus the add mass = 5.465 kg

7 0

3 years ago

What do all types of waves on the electromagnetic spectrum have in common

const2013 [10]

They all travel by the same speed and light

4 0

3 years ago

Read 2 more answers

One horsepower is a unit of power equal to 746 W. How much energy can a 150-horsepower engine transform in 10.0 s?

Lelu [443]

Answer:

$E = 1119000\ joules$

Explanation:

Given:

$1\ Hp = 746\ watt$

time (t = 10.0 sec)

power = 150 Hp

We need to find the energy transformed by a 150 Hp engine in 10 s.

Solution:

First we convert 150 Hp in watt.

$1\ Hp = 746\ watt$

$150\ Hp = 150\times 746\ watt$

$150\ Hp = 111900\ watt$

So, power (p = 111900 watt)

We know that, if we multiply power by time, we get energy transform by engine.

$P = \frac{E}{t}$

$E = P\times t\ joule$ -----------(1)

Where:

P ⇒ power.

E ⇒ Energy.

t ⇒ time.

Substitute p = 111900 watt and t = 10 s in equation 1.

$E = 111900\times 10$

$E = 1119000\ joules$

Therefore, a 150 Hp engine could transform 1,119,000 joules energy in 10 s.

4 0

3 years ago