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Varvara68 [4.7K]
3 years ago
14

What do all types of waves on the electromagnetic spectrum have in common

Physics
2 answers:
Gennadij [26K]3 years ago
7 0

Answer:

They have the same rate of motion

Explanation:

const2013 [10]3 years ago
4 0
They all travel by the same speed and light
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Studies show that the amount of heat stored in the ocean is increasing. What effect might this have?
g100num [7]
This warming will have an effect on the bicarbonate buffer of the ocean.
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3 years ago
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g Suppose that you seal an ordinary 60W lightbulb and a suitable battery inside a transparent enclosure and suspend the system f
Lady_Fox [76]

Answer:

kekemeeimdeiddnekem

Explanation:

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5 0
3 years ago
A child's top is held in place upright on a frictionless surface. The axle has a radius of ????=3.21 mm . Two strings are wrappe
tekilochka [14]

Answer:

Angular momentum, L=6.47\times 10^{-3}\ m

Explanation:

It is given that,

Radius of the axle, r=3.21\ mm=3.21\times 10^{-3}\ m

Tension acting on the top, T = 3.15 N

Time taken by the string to unwind, t = 0.32 s

We know that the rate of change of angular momentum is equal to the torque acting on the torque. The relation is given by :

\tau=\dfrac{dL}{dt}

Torque acting on the top is given by :

\tau=F\times r

Here, F is the tension acting on it. Torque acting on the top is given by :

\tau=2F\times r

2T\times r=\dfrac{L}{t}

L=2T\times r \times t

L=2\times 3.15\times 3.21\times 10^{-3}\times 0.32

L=6.47\times 10^{-3}\ m

So, the angular momentum acquired by the top is 6.47\times 10^{-3}\ m. Hence, this is the required solution.

7 0
4 years ago
Choose the law each sentence describes. This law relates a planet's orbital period and its average distance to the Sun. The orbi
hram777 [196]

These are the Kepler's laws of planetary motion.

This law relates a planet's orbital period and its average distance to the Sun. - Third law of Kepler.

The orbits of planets are ellipses with the Sun at one focus. - First law of Kepler.

The speed of a planet varies, such that a planet sweeps out an equal area in equal time frames. - Second law of Kepler.

7 0
3 years ago
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in a hydraulic garage the small piston has a radius of 5 cm and the large piston has radius of 15 cm what force must be applied
viktelen [127]

The force applied to small piston = 2.2 x 10³ N

<h3>Further explanation</h3>

Given

a radius of 5 cm and 15 cm

weight 20000 N

Required

Force applied

Solution

Pascal Law :

F₁/A₁=F₂/A₂

A₁ = π.5²

A₂ = π.15²

F₁/ π.5² cm² = 20000/π.15² cm²

F₁ = 2222.22 N⇒2.2 x 10³ N

5 0
3 years ago
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