Answer:
r=4.55 x 10^-14 m
Explanation:
<u>Identify the unknown: </u>
<em>How close to the gold nucleus could alpha particles come before being deflected? </em>
<u>List the Knowns:
</u>
Charge of alpha particle: Q_1 = 2 x 1.6 x 10^-19 C
Energy of alpha particle: K.E = 4.5 x 10^6 eV = 5 x 10^6 x 1.6 x 10^-19 J
Charge of gold nucleus: Q_2 = 79 x 1.6 x 10^-19 C
Electric force constant: k = 9 x 10^9 N • m^2/c^2
<u>Set Up the Problem: </u>
The alpha particles will be repelled by the gold nucleus and it will approaches until all its kinetic energy transformed into electrical potential energy. so at this distance from the gold nucleus, potential energy equals KE
Potential energy of a two-charge system:
U(r)=k*Q_1*Q_2/r
r=k*Q_1*Q_2/
U
Solve the Problem:
r=4.55 x 10^-14 m
The answer is C creating proteins and ik this because I had the same answer and my teacher helped me
The crust since it is the outermost layer. Both the cores and the mantle are underground and are involved in very high temperatures. Answer is the crust
Answer:
Newton's second law says that F=ma, so if the force applied is zero, then the acceleration must also be zero.
Explanation:
Let's set the equation to 0 = ma. If mass is a nonzero value, then the acceleration must be zero to solve the equation. Therefore, if the force applied to an object is zero, then it will not accelerate (i.e. change speed or direction).
