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Anton [14]
3 years ago
11

9y + 6 + 2(5 + y) = blank y + blank

Mathematics
2 answers:
maria [59]3 years ago
5 0

Answer:

<h2><em>1</em><em>1</em><em>y</em><em>+</em><em>1</em><em>6</em></h2>

<em>Solution</em><em>,</em>

<em>9y + 6 + 2(5 + y) \\  = 9y + 6 + 10 + 2y \\  combine \: like \: terms \\  = 9y + 2y + 6 + 10 \\ simplify \\  = 11y + 16</em>

<em>hope </em><em>this </em><em>helps.</em><em>.</em><em>.</em>

<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em>

bonufazy [111]3 years ago
4 0

Answer:

11y+16

Step-by-step explanation:

9y+6+2(5+y)=

9y+6+10+2y=

<em>Combine like terms</em>

11y+6+10=

11y+16

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4. Two savings accounts each start with a $200 principal and have an interest rate of 5%. One account earns simple interest and
slega [8]

Answer:

The compounded annually account will earn more interest over 10 years

Step-by-step explanation:

The rule of the simple interest is I = Prt, where

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The rule of the compounded interest is A = P(1+\frac{r}{n})^{nt}, where

  • A is the new value
  • P is the original value
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The interest I = A - P

∵ Each account start with $200

∴ P = 200

∵ They have an interest rate of 5%

∴ r = 5% = 5 ÷ 100 = 0.05

∵ One account earns simple interest and the other is compounded  

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∴ n = 1 ⇒ compounded annually

∵ The time is 10 years

∴ t = 10

→ Substitute these values in the two rules above

∵ I = 200(0.05)(10)

∴ I = 100

∴ The simple interest = $100

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∵ A = 200(1+\frac{0.05}{1})^{1(10)}

∴ A = 325.7789254

∵ I = 325.7789254 - 200

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∴ The compounded interest = $125.7789254

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∵ The compounded interest is $125.7789254

∵ $125.7789254 > $100

∴ The compounded annually account will earn more interest

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6 0
3 years ago
Suppose the system of linear equations has infinitely many solutions. What is the value of y for the second equation?
Otrada [13]
I believe it would be 4

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6 0
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lord [1]

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If a population is the entire school faculty, a sample of the population could be math teachers.

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7 0
2 years ago
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gogolik [260]

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Answer:

<h3>i think 30×12(-64)</h3>

do this simplification

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4 0
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