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3 years ago

9y + 6 + 2(5 + y) = blank y + blank

Mathematics

2 answers:

maria [59]3 years ago

5 0

Answer:

Solution,

 $9y + 6 + 2(5 + y) \\ = 9y + 6 + 10 + 2y \\ combine \: like \: terms \\ = 9y + 2y + 6 + 10 \\ simplify \\ = 11y + 16$ 

hope this helps...

Good luck on your assignment..

bonufazy [111]3 years ago

4 0

Answer:

11y+16

Step-by-step explanation:

9y+6+2(5+y)=

9y+6+10+2y=

Combine like terms

11y+6+10=

11y+16

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Solve 4(3x+3)=15x+7-3x+5

Flura [38]

Answer:

Infinite amount of solutions

Step-by-step explanation:

Step 1: Write equation

4(3x + 3) = 15x + 7 - 3x + 5

Step 2: Solve for x

Distribute 4: 12x + 12 = 15x + 7 - 3x + 5
Combine like terms: 12x + 12 = 12x + 12
Subtract 12 on both sides: 12x = 12x
Divide both sides by 12: x = x

Here, we can see that x would be infinite amount of solutions. We can plug in any number x and it would render the equation true.

4 0

3 years ago

Simplify 3x² × 4x³ ÷ 2x

svp [43]

Answer:

6x^4

Step-by-step explanation:

4 0

3 years ago

I tried this few times in yeah so i could not find it.

Step2247 [10]

Answer:

5 is the answer

Step-by-step explanation:

$\dfrac{ \left( 44+ { 9 }^{ 2 } \right) }{ { 5 }^{ 2 } }$

Calculate 9 to the power of 2 and get 81

$\dfrac{ 44+81 }{ { 5 }^{ 2 } }$

Add 44 and 81 to get 125

$\dfrac{ 125 }{ { 5 }^{ 2 } }$

Calculate 5 to the power of 2 and get 25

$\frac{125}{25}$

Divide 125 by 25 to get 5

$5$

7 0

3 years ago

What is the common difference of the sequence below?

vagabundo [1.1K]

Answer:

Step-by-step explanation:

In finding the COMMON DIFFERENCE, subtract the 2nd term and the first term.

a1 = -4

a2 = -2

Let "d" representing the COMMON DIFFERENCE.

d = -2 -(-4)

d = -2 + 4

d = 2

ANSWER:

THE COMMON DIFFERENCE OF THIS SEQUENCE IS 2

3 0

3 years ago

Read 2 more answers

Find the radius of convergence, r, of the series. ? n2xn 7 · 14 · 21 · ? · (7n) n = 1

defon

I'm guessing the series is supposed to be

$\displaystyle\sum_{n=1}^\infty\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}$

By the ratio test, the series converges if the following limit is less than 1.

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7\cdot14\cdot21\cdot\cdots\cdot(7n)\cdot(7(n+1))}}{\frac{n^2x^n}{7\cdot14\cdot21\cdot\cdots\cdot(7n)}}\right|$

The first $n$ terms in the numerator's denominator cancel with the denominator's denominator:

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2x^{n+1}}{7(n+1)}}{n^2x^n}\right|$

$|x^n|$ also cancels out and the remaining factor of $|x|$ can be pulled out of the limit (as it doesn't depend on $n$ ).

$\displaystyle|x|\lim_{n\to\infty}\left|\frac{\frac{(n+1)^2}{7(n+1)}}{n^2}\right|=|x|\lim_{n\to\infty}\frac{|n+1|}{7n^2}=0$

which means the series converges everywhere (independently of $x$ ), and so the radius of convergence is infinite.

3 0

3 years ago