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Cloud [144]
3 years ago
13

Merry and bright? A string of Christmas lights con-

Mathematics
1 answer:
aksik [14]3 years ago
4 0

Answer:

0.6676

Step-by-step explanation:

given that A string of Christmas lights con-

tains 20 lights. The lights are wired in series, so that

if any light fails, the whole string will go dark. Each

light has probability 0.98 of working for a 3-year

period.

Each light is independent of the other.

The probability that the string of lights will

remain bright for 3 years.​

= Probability that each light does not fail

= multiplication (prob of one light does not fail)

=0.98^{20} \\=0.6676

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Complete Question

The complete question is shown on the first uploaded image  

Answer:

Yes the students are reasonably good at estimating one​ minute

a

  Option A is  correct

b

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Step-by-step explanation:

From the question we are told that

    The  set of data is  

               68, 82 ,  38 ,  62 , 41, 25 , 57 ,  64, 67, 47, 61, 71, 91, 87, 64

     The  population mean is  \mu  = 60

The  level of significance is given as\alpha =  0.01

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         Z_{\alpha } =  2.33

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           H_o  :  \mu  =  60 \ seconds

   The alternative hypothesis is  

          Ha :  \mu \ne 60 \ seconds      

Generally the sample mean is mathematically represented as

       \= x  =  \frac{\sum x_i }{n  }

where  n = 15

 So  

      \= x  =  \frac{ 68+ 82 +  38 +  62 + 41+ 25 + 57 + 64+67+ 47+ 61+ 71+ 91+ 87+ 64}{15}

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The standard deviation is mathematically represented as

     \sigma  =\sqrt{  \frac{ \sum  (x_i -  \= x )^2}{n} }

substituting values

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The  test statistics is evaluated as  

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substituting values

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