25.8%
First, determine how many standard deviations from the norm that 3 tons are. So:
(3 - 2.43) / 0.88 = 0.57/0.88 = 0.647727273
So 3 tons would be 0.647727273 deviations from the norm. Now using a standard normal table, lookup the value 0.65 (the table I'm using has z-values to only 2 decimal places, so I rounded the z-value I got from 0.647727273 to 0.65). The value I got is 0.24215. Now this value is the probability of getting a value between the mean and the z-score. What I want is the probability of getting that z-score and anything higher. So subtract the value from 0.5, so 0.5 - 0.24215 = 0.25785 = 25.785%
So the probability that more than 3 tons will be dumped in a week is 25.8%
To find the unit rate, divide total miles by number of gallons:
418 miles / 16 gallons = 26.125 miles per gallon
Round the answer as needed.
The absolute value makes it 9
He got 16 questions right (5x16=80) and 10 wrong (8x10=80) He got paid $80 but also had to pay $80.
Answer:
Below in bold.
Step-by-step explanation:
In each case you divide top and bottom by the GCF.
A. The GCF of 45 and 56 is 1.
so the answer is 45/56.
B. 15/16 (GCF = 1)
C. Here the GCF is 5 so the answer is (35/5) / (80/5)
= 7/16.
D. 5/6 (GCF is 4).
