1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ch4aika [34]
3 years ago
13

How many atoms of each element are in one molecule of this product.

Chemistry
1 answer:
anastassius [24]3 years ago
7 0
I assume about 5 atoms are in one molecule of this product
You might be interested in
The following chemical reaction occurs in a basic solution.
Dafna1 [17]

Answer:

6 moles of electrons

Explanation:

Let us consider the species NO3− and ClO−. The NO3− is oxidized to NO the oxidation number of nitrogen is decreased from +5 to +2.

The oxidation number of chlorine is increased from +1 to +3. This implies that six electrons were transferred in the balanced reaction equation shown in the question. Hence the answer.

3 0
3 years ago
How many protons are present in one copper(ii) ion?
AlladinOne [14]
Copper has 29 protons, when dealing with Cu^2+ all that means is it lost two electrons. so now the element has 29 protons and 27 electrons. Protons are positive and electrons are negative and neutrons are neutral. So say you had an element X^2- then you have gained two more electrons so the element has an overall negative charge. hope that helps


6 0
3 years ago
The electron configuration for aluminum (Al) is shown below:
Serjik [45]

Answer:

It is the third choice

Explanation:

Just did assignment

3 0
3 years ago
Which chloride is a coloured solid rtp<br>​
lianna [129]

Answer:

sodium chloride

hope that helped :)

7 0
2 years ago
Read 2 more answers
The dissociation of sulfurous acid (H2SO3) in aqueous solution occurs as follows:
aksik [14]

Answer:

The [SO₃²⁻]

Explanation:

From the first dissociation of sulfurous acid we have:

                         H₂SO₃(aq) ⇄ H⁺(aq) + HSO₃⁻(aq)

At equilibrium:  0.50M - x          x            x

The equilibrium constant (Ka₁) is:

K_{a1} = \frac{[H^{+}] [HSO_{3}^{-}]}{[H_{2}SO_{3}]} = \frac{x\cdot x}{0.5 - x} = \frac {x^{2}}{0.5 -x}

With Ka₁= 1.5x10⁻² and solving the quadratic equation, we get the following HSO₃⁻ and H⁺ concentrations:

[HSO_{3}^{-}] = [H^{+}] = 7.94 \cdot 10^{-2}M

Similarly, from the second dissociation of sulfurous acid we have:

                              HSO₃⁻(aq) ⇄ H⁺(aq) + SO₃²⁻(aq)

At equilibrium:  7.94x10⁻²M - x          x            x

The equilibrium constant (Ka₂) is:  

K_{a2} = \frac{[H^{+}] [SO_{3}^{2-}]}{[HSO_{3}^{-}]} = \frac{x^{2}}{7.94 \cdot 10^{-2} - x}  

Using Ka₂= 6.3x10⁻⁸ and solving the quadratic equation, we get the following SO₃⁻ and H⁺ concentrations:

[SO_{3}^{2-}] = [H^{+}] = 7.07 \cdot 10^{-5}M

Therefore, the final concentrations are:

[H₂SO₃] = 0.5M - 7.94x10⁻²M = 0.42M

[HSO₃⁻] = 7.94x10⁻²M - 7.07x10⁻⁵M = 7.93x10⁻²M

[SO₃²⁻] = 7.07x10⁻⁵M

[H⁺] = 7.94x10⁻²M + 7.07x10⁻⁵M = 7.95x10⁻²M

So, the lowest concentration at equilibrium is [SO₃²⁻] = 7.07x10⁻⁵M.

I hope it helps you!

8 0
3 years ago
Other questions:
  • Convert 0.02 g/mL to the unit g/L.
    15·1 answer
  • An element has 15 protons, 11 neutrons, and 17 electrons. What is the name of the<br> element?
    13·1 answer
  • Which has a larger atomic radius, F or F-?
    14·2 answers
  • What is a compounds
    12·1 answer
  • Of organic molecules with similar properties under the same set of conditions, lightest are most likely to be _____ while heavie
    15·1 answer
  • What is the product of the chemical reaction...Au+O2
    9·1 answer
  • Which of the following statements is true? Running an electric current through a magnet can create a magnetic field. Electric en
    8·2 answers
  • Given the elements chlorine, iodine, oxygen, bromine, and fluorine, organize by increasing atomic size (atomic radius). Justify
    5·1 answer
  • Which refers to the bending of a wave as it passes through one medium to another medium?
    8·2 answers
  • The mass of 900. atoms of sodium(Na)
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!