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neonofarm [45]
3 years ago
6

What does Einstein’s theory of relativity expalain?

Chemistry
1 answer:
anygoal [31]3 years ago
8 0

Answer:

The correct answer is D. How gravity interacts with planets

Explanation:

Einstein's theory of relativity formulated in 1915 introduces the following concepts:

- Formula E = mc2 (relationship between energy, mass, speed of light)

- How nuclear energy is produced

-After seeing a solar eclipse, gravity is interpreted geometrically (which is an effect of distortion)

-Relative time

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A salt forms in the reaction of barium with chlorine what is the most likely formula unit of this salt
Mashcka [7]
 Best Answer:<span>  </span><span>LiCl 

Cl and Li 

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BeF2 

last question answer 3 strong electrostatic requires a lot of energy
does this help though??</span>
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2 years ago
The density of iron is about ___ times greater than water.<br><br> 6, 2, 8, 10, or 4
Lelechka [254]

Answer: 4 i think

Explanation:

8 0
2 years ago
Flourine is found to undergo 10% radioactivity decay in 366 minutes determine its halflife​
yuradex [85]

Answer:

\boxed{\text{2408 min}}

Explanation:

The integrated rate law for radioactive decay is

\ln\dfrac{N_{0}}{N_{t}} = kt

1. Calculate the decay constant

\begin{array}{rcl}\ln \dfrac{100}{90} & = & k \times 366\\\\1.054 & = & 366k\\\\k & = & \dfrac{1.054 }{366}\\\\k & = & 2.879 \times 10^{-4} \text{ min}^{-1}\\\end{array}\\\\

2. Calculate the half-life

t_{\frac{1}{2}} = \dfrac{\ln2}{k}\\\\t_{\frac{1}{2}} = \dfrac{\ln2}{2.879 \times 10^{-4} \text{ min}^{-1}} = \text{2408 min}\\\\\text{The half-life for decay is } \boxed{\textbf{2408 min}}

8 0
3 years ago
A semipermeable membrane is placed between the following solutions. Which solution will decrease in volume? Solution A: 1.31% (m
Zigmanuir [339]

Answer:

Are you in flvs, if so im prettyb sure if yo look on page 3 of lesson 1.04 it tells you the answer.

Explanation:

5 0
2 years ago
Read 2 more answers
What is the correct name for TiF3
trapecia [35]

Answer:

Titanium fluoride

Explanation:

6 0
2 years ago
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