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3 years ago

Type of bond between na+1 ion and Cl-1 ion is ion

1 answer:

6 0

A neutral sodium atom, for example, contains 11 protons and 11 electrons. By removing an electron from this atom we get a positively charged Na+ ion that has a net charge of +1. Atoms that gain extra electrons become negatively charged. A neutral chlorine atom, for example, contains 17 protons and 17 electrons.

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What element is least likely to be found in nature

Doss [256]

Answer:

uranium, caesium, potassium, beryllium,

Explanation:

5 0

2 years ago

1.How many mL of 0.401 M HI are needed to dissolve 5.97 g of BaCO3?

garri49 [273]

Answer:

The answer to your question is:

1.- volume = 0.151 l or 151 ml

2.- 0.241 l or 241 ml of NaOH

Explanation:

1.-

Data

V = ? HI = 0.401 M

BaCO3 = 5.97 g

2HI(aq) + BaCO3(s) ⇒ BaI2(aq) + H2O(l) + CO2(g)

MW BaCO3 = 137 + 12 + 48 = 197 g

197 g of BaCO3 ----------------- 1 mol

5.97 g ----------------- x

x = (5.97 x 1) /197

x = 0.03 mol of BaCO3

2 moles of HI ---------------- 1 mol of BaCO3

x ---------------- 0.03 mol of BaCO3

x = (0.03 x 2) / 1

x = 0.060 mol of HI

Molarity = moles / volume

volume = moles / molarity

volume = 0.060 / 0.401

volume = 0.151 l or 151 ml

2.-

V = ? NaoH 0.757 M

Co⁺² Volume = 167 ml 0.548 M

CoSO4(aq) + 2NaOH(aq) ⇒ Co(OH)2(s) + Na2SO4(aq)

Moles of Co = Molarity x volume

Moles of Co = 0.548 x 0.167

Moles of Co = 0.092

1 mol of CoSO4 -------------- 2 moles of NaOH

0.092 moles --------------- x

x = (0.092 x 2) /1

x = 0.183 moles of NaOH

Volume of NaOH = moles / molarity

= 0.183 / 0.757

= 0.241 l or 241 ml of NaOH

6 0

3 years ago

How many moles of oxygen are required to react completely with 5 mol C8H18?

Nata [24]

Answer:

62.5 moles of O₂.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2C₈H₁₈ + 25O₂ —> 16CO₂ + 18H₂O

From the balanced equation above,

2 moles of C₈H₁₈ reacted with 25 moles of O₂.

Finally, we shall determine the number of mole of O₂ needed to react with 5 moles of C₈H₁₈. This can be obtained as shown below:

From the balanced equation above,

2 moles of C₈H₁₈ reacted with 25 moles of O₂.

Therefore, 5 moles of C₈H₁₈ will react with = (5 × 25) / 2 = 62.5 moles of O₂.

Thus, 62.5 moles of O₂ is needed for the reaction.

6 0

3 years ago

Gasoline has a density of .74g/mL. How many milliliter if gasoline have a mass of 2.5kg?

nata0808 [166]

Answer: 3378.4mL

Explanation:

density of Gasoline = 0.74g/mL.

Volume of gasoline in milliliter = ?

mass of gasoline = 2.5kg

(Since density is in grams per millilitre, convert mass in kilograms to grams)

If 1kg = 1000grams

2.5kg = 2.5 x 1000 = 2500grams

Recall that density is obtained by dividing the mass of a substance by its volume

i.e Density = Mass / Volume

0.74g/mL = 2500grams/Volume

Volume = (2500 grams / 0.74g/mL)

Volume = 3378.4mL

Thus, the volume of gasoline is 3378.4mL

4 0

3 years ago

The end point of a titration is defined as the volume of titrant added, while the equivalence point is the volume required for c

saw5 [17]

Answer:

...BY CHOOSING A PROPER INDICATOR, SCIENTISTS CAN MINIMIZE THE DIFFERENCE IN THESE TWO NUMBERS,...

Explanation:

A chemical indicator is an agent or substance which gives a visible sign especially a color change when introduced to a solution of base indicating the threshold of the concentration of acid used in the titration procedure. These indicators include methyl orange, methyl red, phenolpthalein. They give a color change when the concentration of an acid as reached a critical limit in order for the reaction to be stopped. These indicators are involved in acid-base titrations, oxidation- reduction reactions and so on. More accurate results of the volume of the required acid or base is obtained by the introduction of these indicators.

8 0

2 years ago