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Zolol [24]
3 years ago
10

For the process 2SO2(g) + O2(g) --> 2SO3(g),

Chemistry
1 answer:
CaHeK987 [17]3 years ago
8 0

Answer:

–187.9 J/K

Explanation:

The equation that relates the three quantities is:

\Delta G = \Delta H - T \Delta S

where

\Delta G is the Gibbs free energy

\Delta H is the change in enthalpy of the reaction

T is the absolute temperature

\Delta S is the change in entropy

In this reaction we have:

ΔS = –187.9 J/K

ΔH = –198.4 kJ = -198,400 J

T = 297.0 K

So the Gibbs free energy is

\Delta G=-198,400-(297.0)(-187.9)=254.2 kJ

However, here we are asked to say what is the entropy of the reaction, which is therefore

ΔS = –187.9 J/K

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Igneous rock___to form magma a)melts b)weathers c)compacts d)crystallizes NEED HELP ASAP
dangina [55]

Answer:

should be A)Melts.Because magma is liquid i think

5 0
3 years ago
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What is the mathematical relationship between color (wavelength) and energy
Setler [38]
The greater the energy, the larger the frequency and the shorter (smaller) the wavelength. Given the relationship between wavelength and frequency — the higher the frequency, the shorter the wavelength — it follows that short wavelengths are more energetic<span> than long wavelengths.</span>
5 0
3 years ago
Consider the following reaction: COCl2(g) ⇌ CO(g) + Cl2(g) A reaction mixture initially contains 1.6 M COCl2. Determine the equi
professor190 [17]

Answer:

The equilibrium concentration of CO is 0.0361 M

Explanation:

Step 1: Data given

Kc = 8.33 *10^-4

Molarity of COCl2 = 1.6 M

Step 2: The balanced equation:

COCl2(g) ⇌ CO(g) + Cl2(g)

Step 3: Calculate final concentrations

The initial concentration of COCl2 = 1.6M

The initial concentration of CO and Cl2 = 0M

There will react xM of COCl2

Since the mole ratio is 1:1

The final concentration of CO and Cl2 will be X M

The final concentration of COCl2 will be (1.6 -X)M

Step 4: Define Kc

Kc=  [CO] *[Cl2] /  [COCl2]  = 8.33*10^-4

Kc = X*X / 1.6-X = 8.33 * 10^-4

8.33 * 10^-4  = X² /(1.6-X)

8.33 * 10^-4 *(1.6 -X) = X²

0.0013328 - 8.33*10^-4 X = X²

X² + 8.33*10^-4 X  - 0.0013328= 0

X = 0.0361 M = [CO] = [Cl2]

[COCl2] = 1.6 - 0.0361 = 1.5639 M

To control this we can calculate the Kc

(0.0361*0.0361)/1.5639 = 0.000833

5 0
3 years ago
2b. 12 grams of C8H18 react with oxygen to produce carbon dioxide and water. How many grams of CO2 are produced?
likoan [24]

Answer:

37.1g are produced

Explanation:

The combustion of C₈H₁₈ is:

C₈H₁₈ + 25/2O₂ → 8CO₂ + 9H₂O

<em>Where 1 mole of C₈H₁₈ produce 8 moles of CO₂</em>

<em />

To find the mass of CO₂ that is produced we need to convert the mass of C₈H₁₈ with molar mass. Then, with the chemical equation, we can find the moles of CO₂ and its mass, as follows:

<em>Moles C₈H₁₈ -Molar mass: 114.2g/mol-</em>

12g C₈H₁₈ * (1mol / 114.2g) = 0.105 moles of C₈H₁₈

<em>Moles CO₂:</em>

As 1 mole of C₈H₁₈ produce 8 moles of CO₂, 0.105 moles of C₈H₁₈ produce:

0.105 moles of C₈H₁₈ * (8moles CO₂ / 1mole C₈H₁₈) = 0.84 moles of CO₂

<em>Mass CO₂ -Molar mass: 44.01g/mol-:</em>

0.84 moles of CO₂ * (44.01g / mol) = 37.0g of CO₂ ≈

<h3>37.1g are produced</h3>
4 0
2 years ago
How many moles of MgCl2 are produced from 4 moles of HCl
Karolina [17]

Answer:

2 moles of MgCl2.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

Mg + 2HCl —> MgCl2 + H2

Now, we can determine the number of mole MgCl2 produced from 4 moles of HCl as follow:

From the balanced equation above,

2 moles of HCl reacted to produce 1 mole of MgCl2.

Therefore, 4 moles of HCl will react to produce = (4 x 1)/2 = 2 moles of MgCl2.

Therefore, 2 moles of MgCl2 were produced from the reaction of 4 moles of HCl.

5 0
3 years ago
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