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Zolol [24]
3 years ago
10

For the process 2SO2(g) + O2(g) --> 2SO3(g),

Chemistry
1 answer:
CaHeK987 [17]3 years ago
8 0

Answer:

–187.9 J/K

Explanation:

The equation that relates the three quantities is:

\Delta G = \Delta H - T \Delta S

where

\Delta G is the Gibbs free energy

\Delta H is the change in enthalpy of the reaction

T is the absolute temperature

\Delta S is the change in entropy

In this reaction we have:

ΔS = –187.9 J/K

ΔH = –198.4 kJ = -198,400 J

T = 297.0 K

So the Gibbs free energy is

\Delta G=-198,400-(297.0)(-187.9)=254.2 kJ

However, here we are asked to say what is the entropy of the reaction, which is therefore

ΔS = –187.9 J/K

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If the enthalpy change of a reaction in a flask is δh = +67 kj, what can be said about the reaction?
ziro4ka [17]
Answer : Normally in any chemical reaction, if the enthalpy change i.e. ΔH is positive which means it is greater than zero then it can be called as an Endothermic Reaction.

Whereas, the system under study is absorbing heat that is produced during the reaction. So if  ΔH  is found to be positive then it can be called as endothermic reaction.
3 0
3 years ago
Read 2 more answers
Determine how many ml of water you need to remove, by evaporation, if you have a 500 ml of 10.20 M HNO3 dilute solution and you
Ludmilka [50]

The total volume of water that would be removed will be 75 mL

<h3>Dilution equation</h3>

Using the dilution equation:

M1V1 = M2V2

In this case, M1 = 500 mL, V1 = 10.20 M, M2 = 12 M

Substitute:

V2 = 500 x 10.20/12

         = 425 mL

The final volume in order to arrive at 12 M HNO3 would be 425 mL from the initial 500 mL. Thus, the total amount of water that will be removed by evaporation can be calculated as:

500 - 425 = 75 mL

More on dilution can be found here: brainly.com/question/7208939

7 0
2 years ago
The main reason that it's important to test only one variable at a time is so that
bonufazy [111]

D. quantitative data can be recorded.

7 0
3 years ago
Give an example of an element that would be expected to share similar chemical properties with beryllium, calcium, and strontium
Aleks04 [339]
Strontium possibly but I’m not 100% sure
4 0
3 years ago
4. How many grams of hydrogen is produced from 12.5 g of Mg reacting with hydrochloric acid in this
Volgvan

From the reactions, 1.04 g of H2 and 7.995 g of aluminum phosphate is produced.

<h3>What is stoichiometry?</h3>

The term stoichiometry has to do with the amount of substances that participates in a reaction.

For reaction 1;

Mg + 2HCl → MgCl₂ + H₂

Number of moles of Mg reacted =  12.5 g/24g/mol = 0.52 moles

If 1 mole of Mg produced 1 mole of H2

0.52 moles produces 0.52 moles of H2

Mass of H2 =  0.52 moles * 2 g/mol = 1.04 g

For reaction 2;

2Li3PO4 + Al2(SO4)3 → 3Li2SO4 + 2AIPO4

Number of moles of lithium phosphate =  7.5 g/116 g/mol = 0.065 moles

2 moles of Li3PO4 produced 2 moles of AIPO4

0.065 moles of  Li3PO4 produced 0.065 moles of AIPO4

Mass of AIPO4  = 0.065 moles  * 123 g/mol = 7.995 g

Learn more about stoichiometry:brainly.com/question/9743981

#SPJ1

8 0
2 years ago
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