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kati45 [8]
3 years ago
8

How many grams of boiling water must be added to an insulated cup containing 19 grams of ice, at 0oC, to completely melt the ice

Chemistry
1 answer:
schepotkina [342]3 years ago
8 0

Answer:

1900grams of boiling water

Explanation:

0,c=19

100,c=19×100

1900grams

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The solubility of silver chloride can be increased by dissolving it in a solution containing ammonia. agcl (s) ag+ (aq) + cl- (a
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The correct equation for the overall reaction can simply be obtained by adding the two separate equations together. Now when you add the two equations together, the overall K can be calculated by multiplying the individual K values. Therefore:<span>

K(overall) = K1 * K2 </span>

K(overall) = (1.6 x 10^-10) * (1.5 x 10^7)

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A single serving bag of snack chips contains 65.0 Cal. Assuming that all of the energy from eating these chips goes toward keepi
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Answer:

= 62.1 hours

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Energy provide by the serving is 65 cal

= 65 cal  × 4.184 Kj = 271.96 kJ

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3 years ago
The frequency factors for these two reactions are very close to each other in value. Assuming that they are the same, compute th
MrRissso [65]

The question is incomplete, complete question is :

The frequency factors for these two reactions are very close to each other in value. Assuming that they are the same, compute the ratio of the reaction rate constants for these two reactions at 25°C.

\frac{K_1}{K_2}=?

Activation energy of the reaction 1 ,Ea_1 = 14.0 kJ/mol

Activation energy of the reaction 2,Ea_1  = 11.9 kJ/mol

Answer:

0.4284 is the ratio of the rate constants.

Explanation:

According to the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

The expression used with catalyst and without catalyst is,

\frac{K_2}{K_1}=\frac{A\times e^{\frac{-Ea_2}{RT}}}{A\times e^{\frac{-Ea_1}{RT}}}

\frac{K_2}{K_1}=e^{\frac{Ea_1-Ea_2}{RT}}

where,

K_2 = rate constant reaction -1

K_1 = rate constant reaction -2

Activation energy of the reaction 1 ,Ea_1 = 14.0 kJ/mol = 14,000 J

Activation energy of the reaction 2,Ea_1  = 11.9 kJ/mol = 11,900 J

R = gas constant = 8.314 J/ mol K

T = temperature = 25^oC=273+25=298 K

Now put all the given values in this formula, we get

\frac{K_1}{K_2}=e^{\frac{11,900- 14,000Jl}{8.314 J/mol K\times 298 K}}=2.3340

0.4284 is the ratio of the rate constants.

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3 years ago
Which general equation shows a Single-displacement reaction?
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6 0
1 year ago
EXPERIMENT: THE CABBAGE INDICATOR
Nikitich [7]

Answer:

EXPERIMENT: THE CABBAGE INDICATOR

Here are your goals for this lesson:

Use indicator for each substance to determine if substance is an acid or a base

Summarize results and the experimental method

You can use the natural indicator in red cabbage juice to determine which household liquids are acids or bases. If no change in the color of the cabbage juice takes place, the liquid is neither an acid nor base; it is neutral.

Acids and bases are opposites. When an acids and base are mixed, they neutralize each other. You can use an indicator to see the neutralized reaction. The cabbage juice will change color when the liquids are neutralized.

Online Lab

This video will demonstrate how an indicator, in this case, cabbage indicator, can be used to determine whether a solution is acidic or basic. As you watch the video, remember to record your data and observations to use to present your findings.

Compile a summary of your findings from this experiment. Include your hypothesis, observations, data, and conclusions. Be sure to answer the questions below as well as explaining the method and results.

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Explanation:

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1 year ago
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