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liq [111]
3 years ago
5

Point A is located at negative 4 over 6 and point B is located at negative 1 over 6. What is the distance between points A and B

?
( btw this is fractions)
A. negative 4 over 6 minus negative 1 over 6 = negative 3 over 6; therefore, the distance from A to B is absolute value of negative 3 over 6 equals negative 3 over 6 units
B. negative 4 over 6 minus negative 1 over 6 = negative 3 over 6; therefore, the distance from A to B is absolute value of negative 3 over 6 equals 3 over 6 units
C. negative 4 over 6 plus negative 1 over 6 = negative 5 over 6; therefore, the distance from A to B is absolute value of negative 5 over 6 equals 5 over 6 units
D. negative 4 over 6 plus negative 1 over 6 = negative 5 over 6; therefore, the distance from A to B is absolute value of negative 5 over 6 equals negative 5 over 6 units
Mathematics
2 answers:
Alja [10]3 years ago
5 0
The answer is C. negative 4 over 6 plus negative 1 over 6=negative 5 over 6; therefore, the distance from A to B is absolute value of negative 5 over 6 equals 5 over 6 units.
Temka [501]3 years ago
5 0

Hello,

The correct answer is C) Negative 4 over 6 plus negative 1 over 6 = negative 5 over 6; therefore, the distance from A to B is absolute value of negative 5 over 6 equals 5 over 6 units.

Hope this helps!!!! :)

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Try 64. I think its right. I could be wrong though

Step-by-step explanation:

3 0
3 years ago
In a sample of 42 water specimens taken from a construction site, 26 contained detectable levels of lead. Construct a 95% conden
S_A_V [24]

Answer:

The 95% confidence interval for the proportion of water specimens that contain detectable levels of lead is (0.472,0.766).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

In a sample of 42 water specimens taken from a construction site, 26 contained detectable levels of lead.

This means that n = 42, \pi = \frac{26}{42} = 0.619

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.619 - 1.96\sqrt{\frac{0.619*0.381}{42}} = 0.472

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.619 + 1.96\sqrt{\frac{0.619*0.381}{42}} = 0.766

The 95% confidence interval for the proportion of water specimens that contain detectable levels of lead is (0.472,0.766).

4 0
3 years ago
Yes im dumb but i pretty much missed my education of 7th and now im 8th personal reasons and i need to at least get my grades up
Diano4ka-milaya [45]

Answer:

1. A    

2. B      

3.  (-3.5 , -6) --- III

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7 0
3 years ago
Which r-value suggests a strong negative correlation? A. r=0.97351 B. r= -0.27331 C. r= -0.97351 D. r= 0.27331
Archy [21]
Its C hope this helps
6 0
3 years ago
Joshua uses a rule to write the following sequence of numbers 1/6,1/2,5/6,----------,11/2 What rule did Joshua use? What is the
Pani-rosa [81]

Answer: The missing number in the sequence is \frac{7}{6}

Step-by-step explanation:

Since we have given that

\frac{1}{6},\frac{1}{2},\frac{5}{6},----------,\frac{11}{2}

First term = a= \frac{1}{6}

Common difference = d is given by

d=a_2-a_1\\\\\frac{1}{2}-\frac{1}{6}\\\\=\frac{6-2}{12}\\\\=\frac{4}{12}=\frac{1}{3}\\\\Similarly,\\d=a_3-a_2\\\\=\frac{5}{6}-\frac{1}{2}\\\\=\frac{10-6}{12}\\\\=\frac{4}{12}\\\\=\frac{1}{3}

Therefore, it forms an arithmetic sequence.

Since, a_4 is missing,

So,

a_4=a+3d\\\\a_4=\frac{1}{6}+3\times \frac{1}{3}\\\\a_4=\frac{1}{6}+1\\\\a_4=\frac{1+6}{6}\\\\a_4=\frac{7}{6}

Hence, the missing number in the sequence is \frac{7}{6}

4 0
3 years ago
Read 2 more answers
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