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3 years ago

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A store has 20% off sale on pants. With this discount the price of one pair of pants before tax is $15.20. What was the original

price of the pants?

1 answer:

Y_Kistochka [10]3 years ago

5 0

Answer:

<h2>Answer :</h2>

The original price is x, so 20% of x, - x, equals the sale price. You can use the equation:

x-.2x=15.20

.8x=15.20

/.8. /.8

x=19

have a nice day <3

Step-by-step explanation:

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Please help, I dont know where to start

PtichkaEL [24]

Answer:

16 ft

Step-by-step explanation:

The circumference of a circle is given by

C = pi d

where d is the diameter

50.24 = 3.14 *d

Divide each side by 3.14

50.24/ 3.14 = 3.14d/3.14

16 = d

4 0

3 years ago

The EPA wants to know the daily level of pollutant discharge in the manufacturing district in Pittsburgh for February 2005. The

dangina [55]

Answer:

The 95% confidence interval for the true population mean of pollutant discharge is (26.7 tons, 33.7 tons).

Step-by-step explanation:

Let <em>X</em> represent the daily level of pollutant discharge in the manufacturing district in Pittsburgh.

The monitoring equipment reveals that for the 28 days of the February month

Mean daily discharge per factory, ( $\bar x$ ) = 30.2 tons

Standard deviation daily discharge per factory, (<em>s</em>) = 9.1 tons

Compute the critical value of <em>t</em> for 95% level of confidence and (n - 1 =) 27 degrees of freedom as follows:

$t_{0.05/2, 27}=2.052$

*Use a t-table.

Compute the 95% confidence interval for the true population mean of pollutant discharge as follows:

$CI=\bar x\pm t_{\alpha/2, (n-1)}\cdot\frac{s}{\sqrt{n}}$

$=30.2\pm 2.052\times\frac{9.1}{\sqrt{28}}\\\\=30.2\pm 3.53\\\\=(26.67, 33.73)\\\\\approx (26.7, 33.7)$

Thus, the 95% confidence interval for the true population mean of pollutant discharge is (26.7 tons, 33.7 tons).

4 0

3 years ago

Will an object 20ft below sea level have a different absolute value than an object 20ft above sea level .. explain

trapecia [35]

No, the objects below the sea and above both have the absolute value of 20 ft.

The absolute value is how far the number is away from zero- it doesn't matter if it is in the positive or negative direction

For example, if you drove 20 miles from your house in one direction while your friends drove 20 miles in the other direction- both of the distances of you and your friend from the your house is 20 miles.

Distance is a great example of the absolute value because it is always positive. It doesn't matter what direction, it is always 20 miles from your house.

6 0

3 years ago

Indicate the equation of the given line in standard form. The line that is the perpendicular bisector of the segment whose endpo

noname [10]

Well the line that bisects RS, will cut RS in two equal halves, therefore, that line will cut RS perpendicularly at the midpoint of RS.

now, what the dickens is the midpoint of RS anyway?

$\bf \textit{middle point of 2 points }\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
R&({{ -1}}\quad ,&{{ 6}})\quad 
% (c,d)
S&({{ 5}}\quad ,&{{ 5}})
\end{array}\qquad
% coordinates of midpoint 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left( \cfrac{5-1}{2}~~,~~\cfrac{5+6}{2} \right)\implies \stackrel{midpoint}{\left(2~~,~~\frac{11}{2} \right)}$

so, we know that perpendicular line, will have to go through (2, 11/2)

now, a perpendicular line to RS, will have a negative reciprocal slope to it. Well, what is the slope of RS anyway?

$\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({{ -1}}\quad ,&{{ 6}})\quad 
% (c,d)
&({{ 5}}\quad ,&{{ 5}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{5-6}{5-(-1)}\implies \cfrac{5-6}{5+1}\implies -\cfrac{1}{6}$

and let's check the reciprocal negative of that,

$\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad -\cfrac{1}{6}\\\\
slope=-\cfrac{1}{{{ 6}}}\qquad negative\implies +\cfrac{1}{{{ 6}}}\qquad reciprocal\implies + \cfrac{{{ 6}}}{1}\implies 6$

so, then, what's is the equation of a line whose slope is 6, and goes through 2, 11/2?

$\bf \begin{array}{lllll}
&x_1&y_1\\
% (a,b)
&({{ 2}}\quad ,&{{ \frac{11}{2}}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 6
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-\cfrac{11}{2}=6(x-2)
\\\\\\
y-\cfrac{11}{2}=6x-12\implies -6x+y=-12+\cfrac{11}{2}\implies \stackrel{\textit{standard form}}{-6x+y=-\cfrac{13}{2}}$

6 0

2 years ago

HELPPP PLEASEEE FOR 15POINTS

lilavasa [31]

Answer:

I'm not ok. that is too expensive

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers