Which of these elements has four total electrons in its outer p orbital

Ralphie runs north 0.5 km, then turns east and runs 2.0 km, turns south and runs 1.5 km, turns west and runs another 1km. What i

Step2247 [10]

Answer:

I think its 2km

Explanation:

bc if u put it out on a graph, it would essentially take about 4 jumps to get to your ending point, and assuming each jumb was 0.5 km. But if u dont trust me look at another answer bc I dont know if thats right or not.

7 0

3 years ago

if a bicyclist, with initial velocity of zero, steadily gain speed until reaching a final velocity of 26m/s, how far away did sh

Alja [10]

Answer:

Explanation:

Using one of the equation of motion to solve the question. According to the equation v² =u²+2as where;

v is the final velocity of the bicyclist = 26m/s

u is the initial velocity of the bicyclist = 0m/s

a is the acceleration due to gravity = 9.81m/s

s is the distance covered during travel

Substitute the given parameters into the formula above to get the distance traveled

26² = 0² + 2(9.81)s

676 = 19.62s

Divide both sides by 19.62

676/19.62 = 19.62s/19.62

s = 34.46m

<em>The distance traveled by the bicyclist during the race is 34.46m</em>

5 0

4 years ago

by scale drawing, find the resultant of vectors 70N inclined at100N and direction of the resultant 100N

Thepotemich [5.8K]

Answer: 70n=

100n=

Explanation:

4 0

3 years ago

WILL GIVE BRAINLIST

Gnesinka [82]

Answer:

the graph shows the cost of natural hazards in the us in 2011 (in billions of dollars)

Explanation:

it shows that the cost of a tornado happeniy is 30 billion dollars

and the cost of an earthquake is way lower than the one the tornado which is 0 dollar

7 0

2 years ago

Read 2 more answers

A 1500 kg car drives around a flat 200-m-diameter circular track at 25m/s. What are the magnitude and direction of the net force

MakcuM [25]

The correct answer to the question is : 9375 N.

CALCULATION:

As per the question, the mass of the car m = 1500 Kg.

The diametre of the circular track D = 200 m.

Hence, the radius of the circular path R = $\frac{D}{2}$

= $\frac{200}{2}\ m$

= 100 m.

The velocity of the truck v = 25 m/s.

When a body moves in a circular path, the body needs a centripetal force which helps the body stick to the orbit. It acts along the radius and towards the centre.

Hence, the force acting on the car is centripetal force.

The magnitude of the centripetal force is calculated as -

Force F = $\frac{mv^2}{R}$

= $\frac{1500\times (25)^2}{100}\ N$

= 9375 N. [ANS}

The centripetal force is provided to the car in two ways. It is the friction which provides the necessary centripetal force. Sometimes friction is not sufficient. At that time, the road is banked to some extent which provides the necessary centripetal force.

6 0

3 years ago