All categories

3 years ago

Rock at the top of a 20 m tall hill the rock has a mass of 10 kg how much potential energy does it have

Physics

2 answers:

Blizzard [7]3 years ago

6 0

PE = 10 * 10 * 20 = 2000 Joule

vladimir2022 [97]3 years ago

6 0

Answer: 2000Joules

Explanation:

Potential energy is the energy possessed by a body by virtue of its position. A body thrown upward covered a particular height(h) and under the action of gravity(g)

Potential energy = mass × acceleration due to gravity × height

Given mass = 10kg g = 10m/s² height = 20m

Potential energy= 10×10×20

Potential energy = 2,000Joules

Potential energy

You might be interested in

Reference frame definitely changes when what also changes?

kompoz [17]

Explanation is in the file

tinyurl.com/wpazsebu

8 0

3 years ago

Read 2 more answers

The distance from the Earth to the Sun equals 1 AU. Neptune is 30 AU from the Sun. How far is Neptune from the Earth? AU

valina [46]

Answer:

The answer is 29 AU

Hoped I helped

mark me as brainliest

4 0

3 years ago

Read 2 more answers

When is a white dwarf formed?

Anna [14]

When a red giant has insufficient mass it pretty much sheds its outer layer to leave the center core know as the white dwarf

6 0

3 years ago

Read 2 more answers

A 3.7-kg object is acted on by two forces. One of the forces is 11 N acting toward the

vitfil [10]

Answer:

F₂ = -7.3 N

Explanation:

Given that,

The mass of an object, m₁ = 3.7 kg

First force, F₁ = 11 N

The net acceleration of the object is 1 m/s².

We know that,

F₁+F₂ = ma

11+F₂ = (3.7)(1)

F₂ = 3.7-11

F₂ = -7.3 N

so, the other force is 7.3 N and it is acting in west direction.

7 0

3 years ago

A charged box ( m = 495 g, q = + 2.50 μ C ) is placed on a frictionless incline plane. Another charged box ( Q = + 75.0 μ C ) is

Rudik [331]

Answer:

$a=16.2m/s^{2}$

Explanation:

From the attached file diagram, the total force acting on the charged box is the downward weight and the repulsive force acting in opposite to the weight force . Hence we can write the total force as

$F=masin\alpha -\frac{kQq}{r^{2}} \\\alpha =35^{0}, m=0.495kg, r=0.61m, Q=2.5*10^{-6}, q=75.0*10^{-6}\\$

When fixed,F=o

Hence

$masin\alpha =\frac{kQq}{r^{2}}\\0.495kg*asin35=\frac{9*10^{9}*2.5*10^{-6}*75.0*10^{-6}}{0.61^{2}} \\0.28a=4.5351\\a=\frac{4.5351}{0.28}\\\\ a=16.2m/s^{2}$

The value of the acceleration is 16.2m/s^2

7 0

3 years ago