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3 years ago

Rock at the top of a 20 m tall hill the rock has a mass of 10 kg how much potential energy does it have

Physics

2 answers:

Blizzard [7]3 years ago

6 0

PE = 10 * 10 * 20 = 2000 Joule

vladimir2022 [97]3 years ago

6 0

Answer: 2000Joules

Explanation:

Potential energy is the energy possessed by a body by virtue of its position. A body thrown upward covered a particular height(h) and under the action of gravity(g)

Potential energy = mass × acceleration due to gravity × height

Given mass = 10kg g = 10m/s² height = 20m

Potential energy= 10×10×20

Potential energy = 2,000Joules

Potential energy

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Answer:

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Explanation:

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3 years ago

A 3250 N car is pushed a distance of 35 m the power was 11375 J, how long did it take?

irakobra [83]

Answer:

10.8s

Explanation:

Given parameters:

Force on the car = 3250N

Distance = 35m

Power = 11375W

Unknown:

Time taken = ?

Solution:

To solve this problem;

Power is the rate at which work is done

Power = $\frac{work done }{time}$

Work done = force x distance = 3250 x 35 = 123200J

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3 years ago

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Answer:

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2 years ago

Read 2 more answers

Water initially at 200 kPa and 300°C is contained in a piston–cylinder device fitted with stops. The water is allowed to cool at

netineya [11]

Answer:

Δu=1300kJ/kg

Explanation:

Energy at the initial state

$p_{1}=200kPa\\t_{1}=300^{o}\\u_{1}=2808.8kJ/kg(tableA-5)$

Is saturated vapor at initial pressure we have

$p_{2}=200kPa\\x_{2}=1(stat.vapor)\\v_{2}=0.8858m^3/kg(tableA-5)$

Process 2-3 is a constant volume process

$p_{3}=100kPa\\v_{3}=v_{2}=0.8858m^{3}/kg\\u_{3}=1508.6kJ/kg(tableA-5)$

The overall in internal energy

Δu=u₁-u₃

We replace the values in equation

Δu=u₁-u₃

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Δu=1300kJ/kg

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2 years ago

A gas has an initial volume of 212 cm^3 at a temperature of 293 K and a pressure of 0.98 atm. What is the final pressure of the

MatroZZZ [7]

For this we use general equation for gases. Our variables represent:

p- pressure
v-volume
t- temperature

P1V1/T1 = P2V2/T2

in this equation we know:
P1,V1 and T1, T2 and V2.
We have one equation and 1 unknown variable.

P2 = T2P1V1/T1V2 = 1.1atm

8 0

2 years ago