It was once recorded that a Jaguar left skid marks that were 290 m in length. Assuming that the Jaguar had a constant accelerati
on of -3.9 m/s/s, determine the speed of the Jaguar before it began to skid to a stop.
1 answer:
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Answer:
3.06 m
Explanation:
The work done by the man against the gravity is given by
Where F is the force i.e. weight of the man and h is the displacement and
is the angle between displacement and force
Since F=mg and is zero
W = mgh
Also, Work=power* time
Therefore, Power*time=mgh
Substituting power for 120 W, time for 20 seconds, g as 9.81 m/s2 and m as 80 Kg
120*20=80*9.81*h and making he the subject of the formula
Therefore, the height is approximately 3.06 m