HCl = 1 + 35.5 => 36.5 g/mol
hope this helps!
The claim is that NaCl mixture is a homogeneous mixture.
Homogeneous mixture means that the components of the mixtures cannot be determined or separated by the naked eye. However, these components can be separated using physical means, such as boiling, evaporation and condensation which will be used in this experiment.
First, we need to prepare one molar solution of NaCl. To do so, we will dilute a mass of 58.44 grams (molar mass of NaCl) in 1 liter of water.
By this, we will have NaCl solution.
We can notice that once the NaCl is diluted in water, all what you can see is a clear solution. You cannot see the separate particles of NaCl in water.
..............> observation I
Now, we will heat this solution until it boils and water starts evaporating. We will place a cold surface above the steam coming out from the boiling solution.
What we will observe is that when all the water evaporates, we can see white precipitate of NaCl in the bottom of the container. Examining the cold surface placed above the steam, we can see that the water has condensed on this surface.
.........>observation II
Based on this, we managed to use boiling, evaporation and condensation (physical methods) to restore the components of the solution separately.
.............>conclusion
Based on observation I, observation II and the conclusion. we were able to prove that NaCl solution is a homogeneous mixture.
Absorption occurs when photons from incident light hit atoms and molecules and cause them to vibrate. The more an object's molecules move and vibrate, the hotter it becomes. This heat is then emitted from the object as thermal energy.
Answer:
i) CCl₄ and Br₂ does not react
ii) CBr₄ + Cl₂ → CCl₄ + Br₂
Explanation:
i) CCl₄ + Br₂ (no reaction)
From the given activity series, we have that chlorine gas, Cl₂, is more reactive than bromine gas, Br₂, therefore, a reaction of CCl₄ + Br₂ will not have a reaction as the propensity for the chlorine to stay combined with the carbon is higher than the ability for bromine to remain combined with or attract the carbon. Therefore, for CCl₄ + Br₂ there is no reaction
ii) CBr₄ + Cl₂
From the given activity series, we have that chlorine gas, Cl₂, is more reactive than bromine gas, Br₂, therefore, a reaction of CBr₄ + Cl₂ will give products that will have the Br in the CBr₄ replaced by the Cl₂ as follows;
CBr₄ + Cl₂ → CCl₄ + Br₂
The products of the reaction of CBr₄ and Cl₂ are therefore CBr₄ and Cl₂.
