Answer:
cost price of a table=$9000
profit%=20%
Let profit be x
to find profit use formula,
profit%=profit/cost price*100
20%=x/$9000*100
20*$9000=100x
$180000/100=x
$1800=x
Now to find selling prie os a table use formula,
cost price +profit
$9000+$1800
$91800
therefore selling price of a table is $91800
Step-by-step explanation:
Hope this helps u!!
3/4+5/6 divided by 2/3 is 8/4 or 2
Do 5/6 divided by 2/3 first to get 5/4
then use 5/4 to +3/4 and the answer is 8/4 or 2
Each waffle weighs 5.97 ounces hope this helps!
Step 1. Solve both inequalities for

:




Step 2. To check a point in the solution of the given system of inequalities, look for the intercepts of the lines

and

:

(1)

(2)
Replace (1) in (2):

Solve for

:


(3)
Replace (3) in (1):



We can conclude that the point (-2,3) is in the solution of the system if <span>
inequalities</span>
; also any point inside the dark shaded area of the graph of the system of inequalities is also a solution of the system.