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3 years ago

A rock at rest has weight 138 n. what is the weight of the rock when it is accelerating downward at 3.5 m/s2?

1 answer:

7 0

The weight of the rock is 138n when accelerating downward at 3.5m/ s2.Weight is a measurement of the force of gravity on an objects mass. Therefore as long as the force of gravity is the same and the mass of the rock is the same the weight should also be the same.

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Middle adulthood marks the time period in which some adults face the fabled midlife crisis. What exactly is that? Do you think y

MariettaO [177]

The middle life crisis occurs for men at age of 39 and for women at age of 44. At this age, people start realizing that they are getting older and experience some physical changes which seem distressful for them.

It affects the sense of accomplishment and progress in career. Due to a midlife crisis, people start engaging in activities to cope with the reality such as wearing clothes that are fashionable, dating someone etc. Yes, I think I will also go through one because it happens with everyone in this age. It can be avoided by accepting the fact that these changes are reality and everyone have to face it one day.

6 0

3 years ago

An ideal spring hangs from the ceiling. A 2.15 kg mass is hung from the spring, stretching the spring a distance d = 0.0895 m fr

Igoryamba

Answer:

The kinetic energy of the mass at the instant it passes back through the equilibrium position is 0.06500 J.

Explanation:

Given that,

Mass = 2.15 kg

Distance = 0.0895 m

Amplitude = 0.0235 m

We need to calculate the spring constant

Using newton's second law

$F= mg$

Where, f = restoring force

$kx=mg$

$k=\dfrac{mg}{x}$

Put the value into the formula

$k=\dfrac{2.15\times9.8}{0.0895}$

$k=235.41\ N/m$

We need to calculate the kinetic energy of the mass

Using formula of kinetic energy

$K.E=\dfrac{1}{2}mv^2$

Here, $v = A\omega$

$K.E=\dfrac{1}{2}m\times(A\omega)^2$

Here, $\omega=\sqrt{\dfrac{k}{m}}^2$

$K.E=\dfrac{1}{2}m\times A^2\sqrt{\dfrac{k}{m}}^2$

$K.E=\dfrac{1}{2}kA^2$

Put the value into the formula

$K.E=\dfrac{1}{2}\times235.41\times(0.0235)^2$

$K.E=0.06500\ J$

Hence, The kinetic energy of the mass at the instant it passes back through the equilibrium position is 0.06500 J.

8 0

3 years ago

The pressure exerted by a gas is 2.0 atm while it has a volume of 350 mL. What would be the volume of this sample of gas at stan

34kurt

Answer:

700 mL or 0.0007 m³

Explanation:

P₁ = Initial pressure = 2 atm

V₁ = Initial volume = 350 mL

P₂ = Final pressure = 1 atm

V₂ = Final volume

Here the temperature remains constant. So, Boyle's law can be applied here.

P₁V₁ = P₂V₂

$\frac{P_1V_1}{P_2}=V_2\\\Rightarrow V_2=\frac{2\times 350}{1}\\\Rightarrow V_2=700\ mL$

So, volume of this sample of gas at standard atmospheric pressure would be 700 mL or 0.0007 m³

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3 years ago

Explain why asleel meedle does not csink on water

Juli2301 [7.4K]

Answer:

upthrust

Explanation:

i think it does not sink in water because of the force pulling it upwards

5 0

3 years ago

Calculate the rate of loss of heat through a glass window of area 200 CM square and thickness 0.5 CM where temperature inside is

saw5 [17]

Answer:

The inner and outer surfaces of a 0.5-cm thick 2-m by 2-m window glass in winter are 10°C and 3°C, respectively. If the thermal conductivity of the glass

Explanation:

7 0

3 years ago