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pickupchik [31]
3 years ago
5

What would happen if you took a really strong metal box and you started teleporting in hundreds and hundreds of small cotton bal

ls until there is no space left and when you are 100% sure there is no more space left u teleport in a small metal ball.
What would happen to the metal box?Would it explode?Or what would happen to it?

Ps:the box was created as just one pice so it doesn’t have any lid or anything.And I know teleportation is still not possible.
Physics
2 answers:
mina [271]3 years ago
5 0
It's your story. You invented teleportation to make an exciting plot. Now go ahead and finish the story, by making up the thrilling climax.
mojhsa [17]3 years ago
4 0
It will not explode since the mass of the cotton balls is so low but rather will most likely break the lock and hinges and come out.
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What is ohms law <br><br><br>PLEASE ANSWER THIS I NEED IT FAST ​
Lorico [155]

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Ohms law states that current is directly proportional to the potential difference across the ends of a conductor provided that temperature and other factors kept constant

V=I(R)

6 0
3 years ago
The equation for the speed of a satellite in a circular orbit around the earth depends on mass. Which mass?
katovenus [111]
<h3><u>Question: </u></h3>

The equation for the speed of a satellite in a circular orbit around the Earth depends on mass. Which mass?

a. The mass of the sun

b. The mass of the satellite

c. The mass of the Earth

<h3><u>Answer:</u></h3>

The equation for the speed of a satellite orbiting in a circular path around the earth depends upon the mass of Earth.

Option c

<h3><u> Explanation: </u></h3>

Any particular body performing circular motion has a centripetal force in picture. In this case of a satellite revolving in a circular orbit around the earth, the necessary centripetal force is provided by the gravitational force between the satellite and earth. Hence F_{G} = F_{C}.

Gravitational force between Earth and Satellite: F_{G} = \frac{G \times M_e \times M_s}{R^2}

Centripetal force of Satellite :F_C = \frac{M_s \times V^2}{R}

Where G = Gravitational Constant

M_e= Mass of Earth

M_s= Mass of satellite

R= Radius of satellite’s circular orbit

V = Speed of satellite

Equating  F_G = F_C, we get  

Speed of Satellite V =\frac{\sqrt{G \times M_e}}{R}

Thus the speed of satellite depends only on the mass of Earth.

6 0
3 years ago
List the rock layers from oldest to youngest
MakcuM [25]

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8 0
2 years ago
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A point charge of 5.7 µc moves at 4.5 × 105 m/s in a magnetic field that has a field strength of 3.2 mt, as shown in the diagram
Sauron [17]

The magnitude of the force on the charge by the influence of the magnetic field will be 6.6*10^-3 N

<h3>What is magnetic force?</h3>

Magnetic force, attraction or repulsion that arises between electrically charged particles because of their motion.The magnitude of the magnetic force acting on the charge is given by:

\rm F=qvBsin\theta

where

The magnitude of the charge   q=5.7\ \mu C =5.7\times 10^{-6} \ C

The velocity of the charge        v=4.5\times 10^5\ \frac{m}{s}

The magnitude of the magnetic field   3.2\ mT=0.0032\ T

The angle between the directions of v and B  \theta =90^o-37^o=53^o

By substituting the values we will get:

F=(5.7\times 10^}-6})(4.5\times 10^5)(0.0032)(Sin53^o)

F=6.6\times 10^{-3}\ N

Hence the magnitude of the force on the charge by the influence of the magnetic field will be 6.6*10^-3 N

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3 0
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The answer would be REFERENCE POINT
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