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Zanzabum
3 years ago
12

I have a balloon that can hold 125,000 mL of air. If I blow up this balloon with 3 moles of oxygen gas at a

Chemistry
1 answer:
matrenka [14]3 years ago
4 0

Answer:

234.35 °C

Explanation:

Given data:

Volume of balloon = 125000 mL

Moles of oxygen = 3 mol

Pressure = 1 atm

Temperature = ?

Solution:

Formula:

PV = nRT

P = Pressure

V = volume

n = number of moles

R = ideal gas constant

T = temperature

Volume of balloon = 125000 mL × 1 L /1000 mL

Volume of balloon = 125 L

Now we will put the values:

Ideal gas constant = R = 0.0821 atm.L/mol.K

PV = nRT

T = PV/nR

T = 1 atm × 125 L/  0.0821 atm.L/mol.K × 3 mol

T= 125  /0.2463 /K

T = 507.5 K

K to °C

507.5 K - 273.15 = 234.35 °C

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214 mmhg

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why would dry cleaners use nonpolar tetrachloroethylene, c2cl4, to get cheeseburger grease out of clothes?
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3 years ago
Which would be considered a substance? Element, Compound, Mixture.
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2 years ago
In an aqueous solution of a certain acid the acid is 4.4% dissociated and the pH is 3.03. Calculate the acid dissociation consta
NeX [460]

Answer:

4.1x10⁻⁵

Explanation:

The dissociation of an acid is a reversible reaction, and, because of that, it has an equilibrium constant, Ka. For a generic acid (HA), the dissociation happens by:

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So, if x moles of the acid dissociates, x moles of H⁺ and x moles of A⁻ is formed. the percent of dissociation of the acid is:

% = (dissociated/total)*100%

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But x = [A⁻], so:

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3 years ago
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