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3 years ago

I have a balloon that can hold 125,000 mL of air. If I blow up this balloon with 3 moles of oxygen gas at a

Chemistry

1 answer:

matrenka [14]3 years ago

4 0

Answer:

234.35 °C

Explanation:

Given data:

Volume of balloon = 125000 mL

Moles of oxygen = 3 mol

Pressure = 1 atm

Temperature = ?

Solution:

Formula:

PV = nRT

P = Pressure

V = volume

n = number of moles

R = ideal gas constant

T = temperature

Volume of balloon = 125000 mL × 1 L /1000 mL

Volume of balloon = 125 L

Now we will put the values:

Ideal gas constant = R = 0.0821 atm.L/mol.K

PV = nRT

T = PV/nR

T = 1 atm × 125 L/ 0.0821 atm.L/mol.K × 3 mol

T= 125 /0.2463 /K

T = 507.5 K

K to °C

507.5 K - 273.15 = 234.35 °C

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