How many moles of lithium nitrate<br> (LINO3) are in 256 mL of a 0.855 M<br> solution?

Use the Lab Report document as a template. Use the descriptions and examples of each part to help you write your Lab Report. You

GarryVolchara [31]

This link might help you!!

https://www.eiu.edu/biology/bio1500/writing_a_lab_report.pdf

6 0

2 years ago

Calculate the pH of a solution with [H+]= 1 x 10^-6M

Pie

Answer:

pH=6

Explanation:

3 0

2 years ago

Needed now can you please help me on this need help on science don't understand

puteri [66]

I think the answer is letter B.

6 0

3 years ago

Read 2 more answers

The decomposition of nitrogen dioxide to nitrogen monoxide and oxygen gas is a second order process as suspected in the previous

lesya [120]

Explanation:

For the given reaction $2NO_{2} \rightarrow 2NO + O_{2}$

Now, expression for half-life of a second order reaction is as follows.

$t_{1/2} = \frac{1}{[A_{0}]k}$ ....... (1)

Second half life of this reaction will be $t_{1/4}$ . So, expression for this will be as follows.

$t_{1/4}$ = $\frac{1}{k} [\frac{1}{[A]_{f}} - \frac{1}{[A_{0}]}]$ ...(2)

where $[A]_{f}$ is the final concentration that is, $\frac{[A]_{0}}{4}$ here and $[A]_{i}$ is the initial concentration.

Hence, putting these values into equation (2) formula as follows.

$t_{1/4}$ = $\frac{1}{k} [\frac{4}{[A]_{0}} - \frac{1}{[A_{0}]}]$

= $\frac{3}{[A_{0}]k}$ ...... (3)

Now, dividing equation (3) by equation (1) as follows.

$\frac{t_{1/4}}{t_{1/2}}$ = $\frac{3}{[A_{0}]k} \times [A_{0}]k$

= 3

or, $t_{1/4}$ = 3 $t_{1/2}$

Thus, we can conclude that one would expect the second half-life of this reaction to be three times the first half-life of this reaction.

6 0

2 years ago

A chemist prepares a solution of aluminum sulfate (Al2(SO4) by weighing out 116.0 g of aluminum sulfate into a 450. mL volumetri

trasher [3.6K]

Answer:

0.0733 mol /dL

Explanation:

Mole -

Moles is denoted by given mass divided by the molecular mass ,

Hence ,

n = w / m

n = moles ,

w = given mass ,

m = molecular mass .

From the information of the question ,

w = 116.0 g

As we know, molecular mass of aluminum sulfate ,

m = 342.15 g/mol

n = w / m

n = 116.0 g / 342.15 g/mol = 0.33 mol

Molarity -

Molarity of a substance , is the number of moles present in a liter of solution .

M = n / V

M = molarity

V = volume of solution in liter ,

n = moles of solute ,

The unit is mol / L ,

Hence , from the question, the value of molarity is asked ,

From the information of the question ,

V = 450 mL ,

Since,

1 mL = 0.01 dL

As, the unit asked in the question is in dL,

V = 4.5 dL

n = 0.33 mol ( as calculated above )

Using the above formula ,

M = n / V

M = 0.33 mol / 4.5 dL

M = 0.0733 mol /dL

M =

5 0

3 years ago

How many moles of lithium nitrate (LINO3) are in 256 mL of a 0.855 M solution?