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babymother [125]
3 years ago
8

What’s the correct answer for this question?

Mathematics
1 answer:
amm18123 years ago
4 0

Answer: choice B

B would be the most logical answer showing that these 2 events are independent.

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What is the Least Common Multiple of x and 3x?
beks73 [17]

Answer:

3

Step-by-step explanation:

If you divide both numbers by x then it's just 1 and 3. LCM of 1 and 3 is 3

6 0
4 years ago
Read 2 more answers
Ivan's has 3/4 pound of hamburger meat. She makes 3 hamburgers patties.each patty weighs the same amount.hiw much dies each hamb
gulaghasi [49]
25 percent
because use quarters as and example
7 0
3 years ago
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The scale on a map says that 6 cm represents 15 km. What distance on the map in centimeters represents 20 kilometers?
ale4655 [162]

Answer:

8 centimeters.

Step-by-step explanation:

6cm\ on\ map\ -> 15km\\

Divide 3 both sides:

2cm\ on\ map\ -> 5km

Multiply 4 on both sides:

8cm\ on\ map\ -> 20km

8cm on the map represents 20km.

4 0
4 years ago
Determine two pairs of polar coordinates for (3,-3) when 0
Xelga [282]

The two pairs of polar coordinates for the given point (3, -3) with 0° ≤ θ < 360° are (3√2, 135°) and (3√2, 315°).

<h3>What is a polar coordinate?</h3>

A polar coordinate is a two-dimensional coordinate system, wherein each point on a plane is typically determined by a distance (r) from the pole (origin) and an angle (θ) from a reference direction (polar axis).

Next, we would determine the distance (r) and angle (θ) as follows:

r = √(3² + (-3)²)

r = √(9 + 9)

r = 3√2.

θ = tan⁻¹(-3/3)

θ = tan⁻¹(-1)

θ = 3π and 7π/4 (second and fourth quadrants).

Converting to degrees, we have:

θ = 135° and 315°.

Read more on polar coordinates here: brainly.com/question/3875211

#SPJ1

Complete Question:

Determine two pairs of polar coordinates for the point (3, -3) with 0° ≤ θ < 360°

5 0
2 years ago
The formula for wind chill C (in degrees Fahrenheit) is given by C = 35.74 + 0.6215T - 35.75v^0.16 + 0.4275Tv^0.16 where v is th
Diano4ka-milaya [45]

Answer:

dC = 2.44

Relative error = 19%

Step-by-step explanation:

C = 35.74 + 0.6215*T - 35.75*v^(0.16) + 0.4275*T*v^(0.16)

Δv = 3 ; ΔT = 1 , v = 23, T = 8

Use differential Calculus

dC = Cv.dv + Ct.dt

Cv = dC/dv = -5.72*v^(-0.84) + 0.0684*T*v^(-0.84)\\Ct = dC/dT = 0.6215 + 0.4275*v^(0.16)\\dC = modulus (Cv.dv) + modulus (CT.dT)\\dC = (-5.72*v^(-0.84) + 0.0684*T*v^(-0.84))* 3 + (0.6215 + 0.4275*v^(0.16))*1\\dC = 2.44

Relative Error

dC / C @(T = 8, v=23)  * 100 = 19 %

8 0
3 years ago
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