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uranmaximum [27]
3 years ago
8

Does Mitosis have body cells or sex cells?

Chemistry
1 answer:
Rufina [12.5K]3 years ago
5 0
2 identical daughter cells
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Which of the following is a factor in natural selection?
Vera_Pavlovna [14]

Answer:

D.

Explanation:

Although all of these answers are similar, it seems that all three are the answer. I am sorry if the answer ends up being B but I'm pretty sure the answer is D. Charles Darwin's evolution theory "evolved", get it, from the natural selection theory. The theory is described as "the process whereby organisms better adapted to their environment tend to survive and produce more offspring." However, some factors that effect natural selection are competition, selection and variation. I believe all three fit the answer and therefore I believe answer D is correct.

5 0
3 years ago
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What is an expression of Boyle's law (k = constant)?
Leni [432]

Answer:

C.) PV = k

Explanation:

Boyle's Law is a variation of the Ideal Gas Law when all variables, except for pressure and volume, are held constant.

Pressure is represented by "P" and volume is represented by "V". In the Ideal Gas Law, pressure and volume are inversely proportional (if one goes up, the other goes down). That being said, the equation which best represents Boyle's Law is PV = k.

6 0
2 years ago
All large radioactive atoms decay into smaller atoms by releasing alpha particles. Each alpha particle has 2 protons, 2 neutrons
anygoal [31]

Answer:

c

Explanation:

3 0
3 years ago
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the temperature of an ideal gas in a sealed 0.7 m^3 container is reduced from 340 k to 270 k. the final pressure of the gas is 4
vivado [14]

Answer: dulimu

Explanation:refer to maxwell…use your duduli

6 0
3 years ago
When 10.0 g of sulfur is combined with 10.0 g of oxygen, 20.0 g of sulfur dioxide is formed. What mass of oxygen would be requir
Illusion [34]

Answer:

Actually, we can answer the problem even without the first statement. All we have to do is write the reaction for the production of sulfur trioxide.

2 S + 3 O₂ → 2 SO₃

The stoichiometric calculations is as follows:

6 g S * 1 mol/32.06 g S = 0.187 mol S

Moles O₂ needed = 0.187 mol S * 3 mol O₂/2 mol S = 0.2805 mol O₂

Since the molar mas of O₂ is 32 g/mol,

Mass of O₂ needed = 0.2805 mol O₂ * 32 g/mol = 8.976 g O₂

3 0
3 years ago
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