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IgorC [24]
3 years ago
6

The reaction of NO(g) + Cl2(g)⇌NOCl(g) + Cl(g) is found to have an equilibrium constant of 1.1×108 at a particular temperature.

What does this mean? Question 1 options: 1) At equilibrium, there is a much higher concentration of reactants than products. 2) At equilibrium, there is a much higher concentration of products than reactants. 3) At equilibrium, there is an equal concentration of reactants and products. 4) At equilibrium, the value of the equilibrium constant depends on the initial concentration(s).
Chemistry
1 answer:
irakobra [83]3 years ago
6 0

Answer:

Option (2) At equilibrium, there is a much higher concentration of products than reactants.

Explanation:

The equilibrium constant for a reaction is simply the ratio of the concentration products raised to their mole ratio divided by the concentration of the reactants raised to their mole ratio.

If the equilibrium constant is close to 1 or 1, it means the concentration of the reactants and products are almost the same. But if the equilibrium constant is large as in the case of the question given above, it means that at equilibrium, the concentration of the products are higher than that of the reactants.

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Write the MOLECULAR EQUATION between iron and copper (II) sulfate.
Aleksandr-060686 [28]

Answer : The balanced molecular equation will be:

Fe(s)+CuSO_4(aq)\rightarrow FeSO_4(aq)+Cu(s)

Explanation :

Molecular equation : It is a balanced chemical reaction in which the ionic compounds are expressed as the molecules instead of component ions.

According to the question, when iron react with copper (II) sulfate then it react to give iron (II) sulfate and copper as a product. In this reaction, iron is more reactive metal than the copper metal. So, it can easily displace copper metal form the solution.

The balanced molecular equation will be:

Fe(s)+CuSO_4(aq)\rightarrow FeSO_4(aq)+Cu(s)

4 0
2 years ago
Balance this equation<br> _Al +_HCI --&gt; _H2 +_AICIz
kumpel [21]

2Al+6HCl⇒3H₂+2AlCl₃

<h3>Further explanation </h3>

Equalization of chemical reaction equations can be done using variables. Steps in equalizing the reaction equation:  

• 1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c etc.  

• 2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index between reactant and product  

• 3. Select the coefficient of the substance with the most complex chemical formula equal to 1  

Reaction

Al+HCl⇒H₂+AlCl₃

  • Give coefficient

aAl+bHCl⇒cH₂+AlCl₃

  • Make equation

Al, left=a, right=1⇒a=1

Cl, left=b, right=3⇒b=3

H, left=b, right=2c⇒b=2c⇒3=2c⇒c=3/2

the equation becomes :

Al+3HCl⇒3/2H₂+AlCl₃ x2

2Al+6HCl⇒3H₂+2AlCl₃

5 0
2 years ago
Please help !! no links !!
Greeley [361]

Answer:

Explanation:

Option B volume is the correct answer

5 0
2 years ago
Jolene wants to experiment with sugar cubes. Which of the following causes a sugar cube to only change physically, not chemicall
Ugo [173]
If you cut the cube and keep all the pieces you are causing only physical change
5 0
3 years ago
how to determine the net charge of the tripeptide Asp-Gly-Leu at pH 7. Can someone show in details and tricks on how to solve it
Ugo [173]

Answer:

0!

Explanation:

  • You need to search your pKa values for Asn (2.14, 8.75), Gly (2.35, 9.78) and Leu(2.33, 9.74), the first value corresponding to -COOH, the second to -NH3 (a third value would correspond to an R group, but in this case that does not apply), and we'll build a table to find the charges for your possible dissociated groups at indicated pH (7), we need to remember that having a pKa lower than the pH will give us a negative charge, having a pKa bigger than pH will give us a positive charge:            

           

                   -COOH         -NH3              

pH 7------------------------------------------------------              

Asn               -                      +

Gly                -                      +

Leu               -                      +

  • Now that we have our table we'll sketch our peptide's structure:

<em>HN-Asn-Gly-Leu-COOH</em>

This will allow us to see what groups will be free to react to the pH's value, and which groups are not reacting to pH because are forming the bond between amino acids. In this particular example only -NH group in Ans and -COOH in Leu are exposed to pH, we'll look for these charges in the table and add them to find the net charge:

+1 (HN-Asn)

-1 (Leu-COOH)

=0

The net charge is 0!

I hope you find this information useful and interesting! Good luck!

5 0
3 years ago
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