C) energy level
Looking at quantum mechanics, we see that electrons exist at certain energy levels. When they get excited, they’ll jump from one energy state to a higher energy state and down. We can the. Look at the color it admits and determine what the energy level is.
Answer:
7 μl /s
Explanation:
Given data:
0.44 mL/min
μl /s = ?
Solution:
First of all we will convert the mL/min to mL/s.
we will divide the given value by 60.
0.44/60
0.007 mL/s
Now we will convert the mL/s to μl /s.
we will multiply the value with 1000.
0.007 × 1000
7 μl /s
The molarity of the zinc chloride solution will be 0.089 M
<h3>Molarity</h3>
Mole of 7.24 g ZnCl2 = 7.24/136.286 = 0.5312 mol
Total volume of water used in preparing the solution = 300 + 300 = 600 mL
Molarity of the solution = mole/volume = 0.5312/0.6 = 0.089 M
The molarity of the zinc chloride solution is, therefore, 0.089 M
More on molarity can be found here: brainly.com/question/8732513
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3rd option please and good luck hope you pass...........
Answer:
<h2>uranium-235 (²³⁵U) and uranium-238 (²³⁸U)</h2>
Explanation:
The gaseous diffusion process utilizes uranium hexafluoride, UF₆, because although it is a solid at room temperature it is easily vaporized. [1] UF6 is not only convenient for its volatility, but also due to the fact that fluorine only consists of the isotope ¹⁹F, meaning the difference in molecular weights for UF6 are purely reliant on 235U and 238U.Here arises another problem however, for the masses of the two uranium isotopes are so nearly equal there is very little separation of 235UF6 and 238UF6 with one pass through a diffuser.Therefore a cascade process is needed to obtain any measurable amount of enrichment. In a cascade the feed stream at diffuser 1 is the UF6 prior to enrichment (meaning it will contain 0.711% 235U and 99.289% 238U) and marks the start of the cascade. There will be hundreds to thousands of diffusers on the upward or enriching side as well as on the downward or depleted side. The slightly enriched UF6 is sent up the cascade process to the next diffuser where it will be enriched again. The slightly depleted UF6 will be sent downward through the cascade where it will also be enriched again. In this way, the enriched uranium keeps getting enriched and sent onward, and the depleted uranium also gets enriched and sent onward. The depleted uranium always gets sent downward where it will eventually be ejected from the downward stream as depleted uranium.
