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miv72 [106K]
3 years ago
15

If k is non zero digit for which base of k is the sum, 1+kk=100 true?

Mathematics
1 answer:
Anna007 [38]3 years ago
4 0
No, i don't think it's true
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Atticus wants to buy 2/3 of a square yard of wrapping paper the paper cost $2.40 per yard how much will Atticus spend on wrappin
balu736 [363]

Atticus will spend $1.60 on wrapping paper.

Step-by-step explanation:

Given,

Cost of paper per yard = $2.40

Atticus wants to buy = 2/3

Cost of 2/3 yards of paper = \frac{2}{3}*2.40

Cost of 2/3 yards of paper = \frac{4.80}{3}

Cost of 2/3 yards of paper = $1.60

Atticus will spend $1.60 on wrapping paper.

Keywords: division, fraction

Learn more about fractions at:

  • brainly.com/question/9607945
  • brainly.com/question/9729310

#LearnwithBrainly

3 0
3 years ago
Could anybody help me (pic attached)​
RideAnS [48]

Answer: 4/3

Step-by-step explanation:

What are the corresponding sides?

4 and 3

8 and 6

9 and 6.75

This is very easy, just make a fraction

4/3 = 4/3

8/6 = 4/3

9/6.75 = 4/3

Hence the answer is 4/3

5 0
3 years ago
What type of angle is shown?​
Strike441 [17]
An obtuse angle because an obtuse is an angle that is greater than 90 degrees but less than 180.
5 0
3 years ago
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The eccentricity e of an ellipse is defined as the number c/a, where a is the distance of a vertex from the center and c is the
Anna71 [15]

Answer:

Check below, please.

Step-by-step explanation:

Hi, there!

Since we can describe eccentricity as e=\frac{c}{a}

a) Eccentricity close to 0

An ellipsis with eccentricity whose value is 0, is in fact, a degenerate one almost a circle. An ellipse whose value is close to zero is almost a degenerate circle. The closer the eccentricity comes to zero, the more rounded gets the ellipse just like a circle. (Check picture, please)

\frac{x^2}{a^2} +\frac{y^2}{b^2} =1 \:(Ellipse \:formula)\\a^2=b^2+c^2 \: (Pythagorean\: Theorem)\:a=longer \:axis.\:b=shorter \:axis)\\a^2=b^2+(0)^2 \:(c\:is \:the\: distance \: the\: Foci)\\\\a^2=b^2 \\a=b\: (the \:halves \:of \:each\:axes \:measure \:the \:same)

b) Eccentricity =5

5=\frac{c}{a} \:c=5a

An eccentricity equal to 5 implies that the distance between the Foci has to be five (5) times larger than the half of its longer axis! In this case, there can't be an ellipse since the eccentricity must be between 0 and 1 in other words:

If\:e=\frac{c}{a} \:then\:c>0 , and\: c>0 \:then \:1>e>0

c) Eccentricity close to 1

In this case, the eccentricity close or equal to 1 We must conceive an ellipse whose measure for the half of the longer axis a and the distance between the Foci 'c' they both have the same size.

a=c\\\\a^2=b^2+c^2\:(In \:the\:Pythagorean\:Theorem\: we \:should\:conceive \:b=0)

Then:\\\\a=c\\e=\frac{c}{a}\therefore e=1

7 0
3 years ago
Solve using substitution.<br><br> y = –1<br> 2x − y = –1
irakobra [83]
X =1 I had this question
8 0
2 years ago
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