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vfiekz [6]
3 years ago
10

What's bigger 60% of 90 or half of 100?

Mathematics
2 answers:
ra1l [238]3 years ago
7 0
60% of 90

= (60/100) x 90

= 6/10 x 90 = 54.

Half of 100 =  (1/2) x 100 = 50.

Therefore 60% of 90 is greater.
dusya [7]3 years ago
6 0
(90/100) x 60 = 54
60% of 90 = 54. 
(100/100) x 50 = 50
50% of 100 = 50

<em>60% of 90 is bigger than 50% (half) of 100. </em>
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A giant tortoise can walk about 1/10 meters per second on land. A cooter turtle can walk about 1/2 meter per second on land. How
timurjin [86]
(1/10) / 1 = 3 / x.....1/10 m to 1 second = 3 m to x seconds
cross multiply
(1/10)(x) = (3)(1)
1/10x = 3
x = 3 / (1/10)
x = 3 * 10/1
x = 30 seconds <====
7 0
4 years ago
The rectangle shown is dilated by a scale factor of 1/5
Harrizon [31]

Answer:

A'B'= 3 cm and B'D' = 1.6 cm

Step-by-step explanation:

First of all, we are told that the scale factor = 1/5

Now,we know that If the scale factor is less than 1, then the dilation is a reduction.

Thus, in this question the dilation is a reduction.

For us to calculate the dimensions of the dilated rectangle, we'll multiply the original dimensions by the scale factor

Thus;

A'B' = AB(1/5)

A'B' = 15(1/5) = 3 cm

B'D' = BD(1/5) = 8(1/5) = 1.6 cm

Thus, The length of each side of the dilated rectangle are;

A'B'= 3 cm and B'D' = 1.6 cm

5 0
3 years ago
Slope = 1.75; (10, 16.5)
vazorg [7]
Do you want the equation of the line given the slope and a point it goes through?

y - y1 = m (x - x1)
y - 16.5 = 1.75 (x - 10)
y - 16.5 = 1.75x -17.5
y = 1.75x - 1
8 0
3 years ago
From a large number of actuarial exam scores, a random sample of scores is selected, and it is found that of these are passing s
Mnenie [13.5K]

<u>Supposing 60 out of 100 scores are passing scores</u>, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

  • The lower limit is 0.5.
  • The upper limit is 0.7.

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of \frac{1+\alpha}{2}.

60 out of 100 scores are passing scores, hence n = 100, \pi = \frac{60}{100} = 0.6

95% confidence level

So \alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 - 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.5

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 + 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.7

The 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

  • The lower limit is 0.5.
  • The upper limit is 0.7.

A similar problem is given at brainly.com/question/16807970

5 0
3 years ago
Help me I need the answer to #2 and #4
Karo-lina-s [1.5K]
Number 2 is 84.13
number 4 is 56
3 0
3 years ago
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