If the diameter of the bar is 0.490 at this load, determine I. the engineering stress and strain, and [2] II. the true stress and strain is 1561. 84 MPa.
<h3>What is strain?</h3>
Strain is a unitless degree of ways a great deal an item receives larger or smaller from an implemented load. Normal stress happens while the elongation of an item is in reaction to an everyday pressure (i.e. perpendicular to a surface), and is denoted via way of means of the Greek letter epsilon.
- L = 20 cm d x 1 = 0.21 cm
- dx 2 = 0.25 cmF=5500 a) σ= F/A1= 5000/(π/4x(0.0025)^2)= 1018.5916 MPa lateral stress= Ad/d1= (0.0021-0.0025)/0.0025 = - 0.1 longitudinal stress (ɛ_l)= -lateral stress/v = -(-0.16)/0.3
- (assuming a poisson's ration of 0.3) ε_l=0.16/0.3 = 0.5333
- b) σ_true= σ(1+ ɛ_I)= 1018.5916(1+0.5333
- = 1561.84 MPa.
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Answer:
Technician A and B both are correct.
Explanation:
According to Technician A, we can stop noise by applying lubricant (Break friction).
According to Technician A, we can stop noise by set-up right position for break pad.
Answer:
true
Explanation:
it is used to describe the family of transit services available to residents of urban area
Answer:

Explanation:
Given that rigid tank is a closed system, the following model is constructed after the First Law of Thermodynamics:



The entropy generation inside the rigid tank is determined by appropriate application of the Second Law of Thermodynamics:



The properties of the steam are obtained from steam tables:
Intial State






Final State






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The acceleration at points A, B and C are respectively; 960 mm²/s, 1600 mm²/s and 600 mm²/s
<h3>What is the acceleration?</h3>
The drum rolls without sliding and as such its' instantaneous center will lie at B. Thus;
V_d = V_c = 160 mm/s
Also, a_d = a_c = 600 mm²/s
Now, formula for velocity at A is;
V_a = r_ab * ω
where ω = 160/(100 - 60)
ω = 4 rad/s
V_a = 60 * 4
V_a = 240 mm/s
Acceleration at A = V_a²/r_ab
Acceleration at A = 240²/60 = 960 mm²/s
Now, V_b = 100 * 4 = 400 mm/s
Acceleration at B = 400²/100 = 1600 mm²/s
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