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igomit [66]
3 years ago
10

It describes the physical and social elements common to this work. Note that common contexts are listed toward the top, and less

common contexts are listed toward the bottom. According to O*NET, what are common work contexts for Construction Carpenters? Check all that apply. Spend time sitting wear common protective or safety equipment face-to-face discussions exposed to hazardous equipment spend time using hands to handle, control, or feel objects, tools, or controls public speaking
Engineering
2 answers:
QveST [7]3 years ago
7 0

Answer:

BCDE

Explanation:

just look at the link, it tells you.

Dafna1 [17]3 years ago
3 0

Answer:

bcde!!

Explanation:

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An aluminum rod is press fitted onto an aluminum collar. The collar has an inner radius of 1 cm and an outer radius of 2 cm. Giv
Anika [276]

The question is incomplete. The complete question is --

An aluminum rod is press fitted onto an aluminum collar. The collar has an inner radius of 1 cm and an outer radius of 2 cm. Given the rod has a diameter of 1.01 cm and the young's modulus of aluminum is 69 GPa, determine the following :

1. the interference value, i

2. the radial pressure at the interference of the collar and the rod

3. the maximum effective stress in the collar

4. if the yield strength of aluminium is 200 MPa and assume a safety factor of 1.5, will the aluminium collar break

Solution:

Given :

Inner radius of the collar = 1 cm

So, inner diameter, $d_1$ = 2 cm

Outer radius of the collar = 12 cm

So, outer diameter, $d_2$ = 4 cm

The aluminium rod diameter, d = 1.01 cm

Now, from the figure, we can see that there will be no interference and so the rod will easily insert inside the collar.

1. So, the interference , i =0

2. The radial pressure is also 0.

3. There will be no stress developed. So the maximum effective stress is 0

4. The collar will not break

8 0
3 years ago
For a fluid with a Prandtl Number of 1000.0, the hydrodynamic layer is thinner than the thermal boundary layers. a) True b) Fals
kvv77 [185]

Answer:

(b)False

Explanation:

Given:

 Prandtl number(Pr) =1000.

We know that   Pr=\dfrac{\nu }{\alpha }

  Where \nu is the molecular diffusivity of momentum

             \alpha is the molecular diffusivity of heat.

 Prandtl number(Pr) can also be defined as

    Pr=\left (\dfrac{\delta }{\delta _t}\right )^3

Where \delta is the hydrodynamic boundary layer thickness and \delta_t is the thermal boundary layer thickness.

So if Pr>1 then hydrodynamic boundary layer thickness will be greater than thermal boundary layer thickness.

In given question Pr>1 so  hydrodynamic boundary layer thickness will be greater than thermal boundary layer thickness.

So hydrodynamic layer will be thicker than the thermal boundary layer.

8 0
4 years ago
A 50000 N plane has wings with a span of 30 m and a chord of 6 m. How much cargo can this plane carry while cruising at 550 km/h
soldi70 [24.7K]

Answer:

The amount of cargo the plane can carry is 8707.89 N

Explanation:

The surface area of the wings facing the air = 30×6×2 × sin(2.5) = 15.7 m²

The speed of the plane 550 km/h = 152.78 m/s

The volume of air cut through per second = 15.7 × 152.78 = 2399.07 m³

The mass of air = Volume × Density = 2399.07 × 0.37 = 887.65 kg

Weight of air = Mass × Acceleration due to gravity = 887.65 × 9.81 = 8707.89 N

Given that the plane is already airborne, the additional cargo the plane can carry is given by the available lift force of the plane.

The amount of cargo the plane can carry = 8707.89 N

8 0
4 years ago
A 750-turn solenoid, 24 cm long, has a diameter of 2.3 cm . A 19-turn coil is wound tightly around the center of the solenoid. P
oksian1 [2.3K]

Answer: 2.26x10^-4 v

Explanation:

Lenght of the selonoid = 24x10^-2m

Diameter of the selonoid = 2.3cm

The radius will then be = 1.15cm = 1.15x10^-2m

The area of the selonoid = ¶r^2 = 3.142 x (1.15x10^-2)^2 = 0.000415m^2.

Number of turns on selonoid N1 is 750

For the small center coil, number of turns N2 is 19.

There is a change in current dI/dt from 0 to 5.1 in 0.7s, dI/dt = (5.1-0)/0.7

dI/dt = 7.29A/s.

Induced EMF on selonoid due to magnetic Flux due to changing current in small coil is given as;

E = -M(dI/dt), where M is the mutual inductance of the coils.

but M = (u°AN1N2)/L, where u°= 4¶x10^-7,

A = area of selonoid,

L = Lenght of selonoid.

M = (4¶X10^-7X0.000415X750X19)/(24X10^-2)

M = 3.096X10^-5H

Induced EMF E = 3.096X10^-5 x 7.29

E = 2.26x10^-4V

6 0
4 years ago
Help please all of the numbers b4 the equal sign are wrong
Nostrana [21]

Answer:

  • 3/5" = 12'
  • 1 3/4" = 35'
  • 1 1/4" = 25'
  • 9/10" = 18'
  • 2 13/20" = 53'

Explanation:

One number is wrong; they all lack units.

The basic ratio is 1" = 20', so you can divide feet by 20 to find inches.

  • 3/5" = 12'
  • 1 3/4" = 35'
  • 1 1/4" = 25'
  • 9/10" = 18'
  • 2 13/20" = 53'

Perhaps you want decimal inches:

  • 0.60" = 12'
  • 1.75" = 35'
  • 1.25" = 25'
  • 0.90" = 18'
  • 2.65" = 53'
7 0
3 years ago
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