To solve this problem it is necessary to apply the concepts related to the heat exchange of a body.
By definition heat exchange in terms of mass flow can be expressed as

Where
Specific heat
= Mass flow rate
= Change in Temperature
Our values are given as
Specific heat of air



From our equation we have that


Rearrange to find 

Replacing


Therefore the exit temperature of air is 53.98°C
Answer:
a) 6.4 mg/l
b) 5.6 mg/l
Explanation:
Given data:
effluent Discharge Q_w = 1.0 m^3.s
Ultimate BOD L_w = 40 mg/l
Discharge of stream Q_r = 10 m^3.s
Stream ultimate BOD L_r = 3 mg/l
a) Ultimate BOD of mixture

b) utlimate BOD at 10,000 m downstream

putting 
t = 0.578 days
we know



Answer:
Please see the attached file for the complete answer.
Explanation:
Answer:
of 5 lb/ft and a concentrated service live load at midspan. .... length = 12 feet) to support a uniformly distributed load. Taking ... w 7..'{ 'f.- ~ s-·. 344 ft-kip. Fy : s-o ks I. 299 ft-kip. Li.. ::::- I 2.. }-t-. 150 ft-kip ..... The concrete and reinforcing steel properties are ... Neglecting beam self-weight . and based only on the ...... JI : Lf, 2. l.. ;VI.
Explanation: