Which observation would be evidence that heat was transferred by radiation

2 answers:

8 0

Radiation is a type of heat transfer wherein there is no need for medium or media through which the heat will flow. Consequently, the radiation waves are able to travel through vacuum. The best observation as evidence to conclude that heat is indeed transferred by radiation is the increase of temperature of the receiving body.

meriva3 years ago

8 0

Answer:

Explanation:

Radiation is a type of heat transfer with use of medium in between or through space. In radiation, energy is emitted or transmitted through a material medium. We can say it by some examples such as :- Due to sunlight earth surface heated, and in heating up of surface air by release of infrared radiations from earth.

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What factors determine the magnitude of the electric force between two particles ?

sattari [20]

Answer:

Force between two particles depends on the magnitude of charge on the particles and distance between them

Explanation:

We know that

According to coulomb's law electric force between two Particles is given by

$F=\frac{1}{4\pi \epsilon _0}\frac{Q_1Q_2}{R^2}=\frac{KQ_1Q_2}{R^2}$ , here K is constant $Q_1\ and\ Q_2\ charge\ on\ the\ particles$

R is the distance between the charge particles

So force between two particles depends on the magnitude of charge on the particles and distance between them

6 0

3 years ago

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60 point!!!

erastova [34]

Answer:

Playing hockey, driving a car, and even simply taking a walk are all everyday examples of Newton's laws of motion.

7 0

3 years ago

One end of a thin rod is attached to a pivot, about which it can rotate without friction. Air resistance is absent. The rod has

Mars2501 [29]

Answer:

6.86 m/s

Explanation:

This problem can be solved by doing the total energy balance, i.e:

initial (KE + PE) = final (KE + PE). { KE = Kinetic Energy and PE = Potential Energy}

Since the rod comes to a halt at the topmost position, the KE final is 0. Therefore, all the KE initial is changed to PE, i.e, ΔKE = ΔPE.

Now, at the initial position (the rod hanging vertically down), the bottom-most end is given a velocity of v0. The initial angular velocity(ω) of the rod is given by ω = v/r , where v is the velocity of a particle on the rod and r is the distance of this particle from the axis.

Now, taking v = v0 and r = length of the rod(L), we get ω = v0/ 0.8 rad/s

The rotational KE of the rod is given by KE = 0.5Iω², where I is the moment of inertia of the rod about the axis of rotation and this is given by I = 1/3mL², where L is the length of the rod. Therefore, KE = 1/2ω²1/3mL² = 1/6ω²mL². Also, ω = v0/L, hence KE = 1/6m(v0)²

This KE is equal to the change in PE of the rod. Since the rod is uniform, the center of mass of the rod is at its center and is therefore at a distane of L/2 from the axis of rotation in the downward direction and at the final position, it is at a distance of L/2 in the upward direction. Hence ΔPE = mgL/2 + mgL/2 = mgL. (g = 9.8 m/s²)

Now, 1/6m(v0)² = mgL ⇒ v0 = $\sqrt{6gL}$