Let the initial velocity of the car be u.
Final velocity of the car (v) = 5.43 m/s
deceleration (a) = - 2.78 m/s^2
Time taken (t) = 2.26 s
Using the first equation of motion:
v = u + at
u = v - at
u = 5.43 + 6.28
u = 11.71 m/s
Let the car's displacement be x.
Using second equation of motion:
x = 26.4646 - 7.0995
x = 19.3651 meters
Hence, the displacement of the car is 19.36 meters
Answer:
d. A projectile with a horizontal component of motion will have a constant horizontal velocity.
f. The horizontal velocity of a projectile is unaffected by the vertical velocity; these two components of motion are independent of each other.
g. The horizontal displacement of a projectile is dependent upon the time of flight and the initial horizontal velocity.
h. The final horizontal velocity of a projectile is always equal to the initial horizontal velocity.
Explanation:
When we are dealing with parabolic motion, the x-component of the velocity remains the same (hence, in the case of the horizontal component, the acceleration will always be zero), <u>while the y-component always change because it is affected by the acceleration due gravity that acts verticaly.</u>
On the other hand, the horizontal displacement of the projectile is mathematically expressed as:
Where:
is the projectile's horizontal component of the initial velocity
is the time the parabolic motion lasts
This means <u>the projectile's horizontal displacement is directly proportional to the horizontal component of the initial velocity and the total time the projectile describes the parabolic motion</u>.
Of course, all of this considerations are assuming this is an ideal parabolic path and there is no air resistance.
Explanation:
this is the ans hope it works
