Question

A 1500 kg car on flat ground is moving 5.25 m/s. Its engine creates a 1250 N forward force as the car moves 42.8 m. What is its final velocity?​

Answer 1

Answer:

9.93 m/s

Explanation:

The following data were obtained from the question:

Mass (m) = 1500 Kg

Initial velocity (u) = 5.25 m/s

Force (F) = 1250 N

Distance (s) = 42.8 m

Final velocity (v) =...?

Next, we shall determine the acceleration of car. This can be achieved as shown below:

Force (F) = mass (m) x acceleration (a)

1250 = 1500 x a

Divide both side by 1500

a = 1250/1500

a = 0.83 m/s²

Therefore, the acceleration of the car is 0.83 m/s²

Now, we can determine the final velocity of car as shown below:

Initial velocity (u) = 5.25 m/s

Distance (s) = 42.8 m

Acceleration (a) = 0.83 m/s²

Final velocity (v) =...?

v² = u² + 2as

v² = (5.25)² + 2 x 0.83 x 42.8

v² = 27.5625 + 71.048

v² = 98.6105

Take the square root of both side

v = √98.6105

v = 9.93 m/s

Therefore, the final velocity of the car is 9.93 m/s