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vova2212 [387]
3 years ago
8

Read the speedometer and report the speed to the proper

Chemistry
1 answer:
Dmitry [639]3 years ago
3 0

Answer:

  • In miles per hour: 82 mph
  • In km/h: 121 km/h

Explanation:

The correct number of digits to report a measure include every certain digit plus one uncertain digit.

The speedometer has marks for:

  • every 2 km per hour, km/h. Because each small tick mark on the outer circle represents 2 mph.

  • every 10 miles per hour mph. Because each small tick mark on the inner scale represents 10 mph.

As a rule you can appreciate up to half way between two small tick marks.

So, for km/h you can appreciate half of 2 km/h, i.e. 1 km/h.

The needle is marking between 120 km/h and 122 km/h, which means that the correct measure is 121 km, where the two leftmost digits are certain and the ones digit is uncertain.

For mph, you can appreciate half of 10 mph, i.e. 5 mph. A measure between 80 and 90 mph should be read as 85 mph.

Furthermore, in this last case of mph, the space between two consecutive marks is broad and equal to 10 mph but also the needle is wide, so it is difficult to appreciate less than 5 mph.

The correct measure must have two significant digits: one certain and one uncertain. So, 82 mph is as correct as 85 mph, since the 8 is certain and the next number (either 2 or 5) is uncertain.

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MissTica

Answer:

temperature before the increase in CO2 was a few degrees lower than temperature after the increase.

Explanation:

CO2 in the atmosphere has the property of trapping heat by absorbing it. So, with increase in the level of CO2 in the atmosphere the more heat will be absorbed by it and hence the temperature before the increase in CO2 was a few degrees lower than temperature after the increase.

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3 years ago
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True....... hope this helps
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4 years ago
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The density of an object is 7.3 g/mL and the volume is 0.94<br> mL. What is the mass of the object?
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Answer:

<h3>The answer is 6.86 g</h3>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

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We have the final answer as

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Hope this helps you

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