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faust18 [17]
3 years ago
14

Jeff used an equal arm balance to weigh a 4.312 g sample of sodium chloride. Which of these measurements made by Jeff is the mos

t accurate? (5 points) 4.5 g 4.1 g 4.2 g 4.3 g
Chemistry
2 answers:
AlladinOne [14]3 years ago
4 0

<u>Answer:</u> The most accurate measurement made by Jeff is 4.3 g

<u>Explanation:</u>

Accuracy is defined as the closeness of a measured value to a standard or known value.

For Example: If the mass of a substance is 58 kg and one person weighed 57 kg and another person weighed 60 kg. Then, the weight measured by first person is more accurate.

We are given:

Mass of the sample = 4.312 g

So, the measurement close to 4.312 grams will be the accurate value.

Hence, the most accurate measurement made by Jeff is 4.3 g

Virty [35]3 years ago
3 0

Answer:

4.3.

Explanation:

  • Measurements that are close to the known value are said to be accurate, whereas measurements that are close to each other are said to be precise.
  • The most closest measurement to the known value is 4.3 g.
  • So, the right choice is: 4.3 g.
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If aluminum has a density of 2.7 g/cm³, what is the volume of 2.7 grams of aluminum?​
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A 48.0g sample of quartz, which has a specific heat capacity of 0.730·J·g−1°C−1, is dropped into an insulated container containi
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Answer:

The equilibrium temperature of the water is 26.7 °C

Explanation:

<u>Step 1:</u> Data given

Mass of the sample quartz = 48.0 grams

Specific heat capacity of the sample = 0.730 J/g°C

Initial temperature of the sample = 88.6°C

Mass of the water = 300.0 grams

Initial temperature = 25.0°C

Specific heat capacity of water = 4.184 J/g°C

<u>Step 2:</u> Calculate final temperature

Qlost = -Qgained

Qquartz = - Qwater

Q =m*c*ΔT

Q = m(quartz)*c(quartz)*ΔT(quartz) = -m(water) * c(water) * ΔT(water)

⇒ mass of the quartz = 48.0 grams

⇒ c(quartz) = the specific heat capacity of quartz = 0.730 J/g°C

⇒ ΔT(quartz) = The change of temperature of the sample = T2 -88.6 °C

⇒ mass of water = 300.0 grams

⇒c(water) = the specific heat capacity of water = 4.184 J/g°C

⇒ ΔT= (water) = the change in temperature of water = T2 - 25.0°C

48.0 * 0.730 * (T2-88.6) -300.0 * 4.184 *(T2 - 25.0)

35.04(T2-88.6) = -1255.2 (T2-25)

35.04T2 -3104.544 = -1255.2T2 + 31380

1290.24T2 = 34484.544

T2 = 26.7 °C

The equilibrium temperature of the water is 26.7 °C

8 0
2 years ago
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