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3 years ago

What is the thinnest type of crust?

Chemistry

1 answer:

Trava [24]3 years ago

8 0

The correct answer is oceanic crust, 80 km, Hope this helps let me know.

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10 Given the balanced ionic equation representing a reaction:

Anon25 [30]

Answer:

Option (A) Each Zn atom loses 2 electrons, and each Co2+ ion gains 2

Explanation:

To know the right answer to the question, let us observe the changes in the oxidation number of Zn and Co. This is illustrated below:

Zn(s) + Co2+(aq) → Zn2+(aq) + Co(s)

The oxidation number of Zn changes from 0 to +2 indicating that Zn has lose 2 electrons.

The oxidation number of Co changes from +2 to 0 indicating that Co has gain 2 electrons.

Therefore, option A is the correct answer.

5 0

4 years ago

Calculate ΔH and ΔStot when two copper blocks, each of mass 10.0 kg, one at 100°C and the other at 0°C, are placed in contact in

ira [324]

Explanation:

The given data is as follows.

m = 10.0 kg = 10,000 g (as 1 kg = 1000 g)

Initial temp. of block 1, $T_{1} = 100^{o}C$ = (100 + 273) K = 373 K

Initial temp. of block 2, $T_{2} = 0^{o}C$ = (0 + 273) K = 273 K

So, heat released by block 1 = heat gained by block 2

$mC \Delta T = mC \times \Delta T$

$10000 g \times 0.385 \times (T_{f} - 100)^{o}C = 10000 g \times 0.385 \times (0 - T_{f})^{o}C$

$T_{f} - 100^{o}C = 0^{o}C - T_{f}$

$2T_{f} = 100^{o}C$

$T_{f} = 50^{o}C$

Convert temperature into kelvin as (50 + 273) K = 323 K.

Also, we know that the relation between enthalpy and temperature change is as follows.

$\Delta H = mC \Delta T$

= $10000 g \times 0.385 J/K g \times 323 K$

= 1243550 J

or, = 1243.5 kJ

Now, calculate entropy change for block 1 as follows.

$\Delta S_{1} = mC ln \frac{T_{f}}{T_{i}}$

= $10000 g \times 0.385 J/K g \times ln \frac{323}{373}$

= $10000 g \times 0.385 J/K g \times -0.143$

= -554.12 J/K

Now, entropy change for block 2 is as follows.

$\Delta S_{2} = mC ln \frac{T_{f}}{T_{i}}$

= $10000 g \times 0.385 J/K g \times ln \frac{323}{273}$

= $10000 g \times 0.385 J/K g \times 0.168$

= 647.49 J/K

Hence, total entropy will be sum of entropy change of both the blocks.

$\Delta S_{total} = \Delta S_{1} + \Delta S_{2}$

= -554.12 J/K + 647.49 J/K

= 93.37 J/K

Thus, we can conclude that for the given reaction $\Delta H$ is 1243.5 kJ and $\Delta S_{total}$ is 93.37 J/K.

6 0

3 years ago

An atomic mass unit is defined as exactly

Rzqust [24]

Answer:Mass of an atom

Explanation:

3 0

3 years ago

Read 2 more answers

What will be the volume of a gas sample at 337 K if its volume at 237 K is 12.0 L? Round your answer to 1 digit after the decima

oksano4ka [1.4K]

Answer:

17.1 L

Explanation:

V1/T1=V2/T2

V2=(V1*T2)/T1

V2= (12.0L * 337K)/237K

V2=17.1L

7 0

4 years ago

18. How many moles of atoms are there in each of

Lelechka [254]

a) 1 mole of Ne

b) i/2 mole of Mg

c) 1570 moles of Pb.

d) 2.18125*10^-13 moles of oxygen.

Explanation:

The number of moles calculated by Avogadro's number in 6.23*10^23 of Neon.

6.23*10^23= 1/ 6.23*10^23

= 1 mole

The number of moles calculated by Avogadro's number in 3.01*10^23 of Mg

3.2*10^23=1/6.23*10^23

= 1/2 moles of Pb.

Number of moles in 3.25*10^5 gm of lead.

atomic weight of Pb=

n=weight/atomic weight

= 3.25*10^5/ 207

= 1570 moles of Pb.

Number of moles 4.50 x 10-12 g O

number of moles= 4.50*10^-12/16

= 2.18125*10^-13 moles of oxygen.

3 0

3 years ago