Answer:
The graph in the attached figure
Step-by-step explanation:
we know that
A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form 
or 
In a proportional relationship the constant of proportionality k is equal to the slope m of the line <u><em>and the line passes through the origin</em></u>
In this problem the given line represent a proportional relationship, because passes through the origin
we have
---> the constant of proportionality k is equal to the slope
substitute
The linear equation is
To draw a line we need two points
we have (0,0)
To find the other point
assume x=3 and substitute in the equation to solve for y
so
The other point is (3,4)
using a graphing tool
Plot the points (0,0) and (3,4)
To graph the line join the points
see the attached figure
Answer:
A) 
B) 
C) 
Step-by-step explanation:
So we have the equation:
Let's write this in function notation. Thus:
A)
To flip a function over the x-axis, multiply the function by -1. Thus:
Simplify:
B) To flip a function over the y-axis, change the variable x to -x. Thus:
Simplify:
C) A reflection over the line y=x is synonymous with finding the inverse of the function.
To find the inverse, switch x and f(x) and solve for f(x):
Switch:
Subtract 4 from both sides:
Divide both sides by 5:
And we're done :)
Whenever it’s to the power of 0 the answer is 1 but idk if it’s negative use photomath
Answer:
the line will have a point at -5, as that is it's y- intercept, and the slope is one so each following point is one diagonal to it on the right side, as the slope is positive
Step-by-step explanation:
Answer:
j² - 5j²k - 2
Step-by-step explanation:
3j² - j²k - 6 - 4j²k - 2j² + 4
To simplify this polynomial, we can collect like terms. A term is number(s) or variable(s) that are grouped together by multiplication. <u>Like terms have the same variable and exponent</u>.
We have three groups of like terms:
The j-squares (j²), the j-squared k (j²k) and the constants (no variable).
Remember to include the negatives!
The j-squares are: 3j² ; -2j²
The j-squares k are: - j²k ; - 4j²k
The constants are: - 6 ; 4
Simplify:
3j² - j²k - 6 - 4j²k - 2j² + 4
Rearrange the polynomial by like terms
= (- j²k - 4j²k) + (3j² - 2j²) + (- 6 + 4)
Add or subtract the like terms
= (-5j²k) + (j²) + (-2)
Remove brackets and rearrange so the negative is not first
= j² + - 5j²k + - 2
Simplify where two signs are together. Adding a negative is subtraction.
= j² - 5j²k - 2 Simplified
