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3 years ago

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The length of a rectangle is 3 meters longer than the width. if the area is 36 square meters, find the rectangle's dimensions.

round to the nearest tenth of a meter.

1 answer:

kompoz [17]3 years ago

8 0

Here you are. you can see my explication.
have fun

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Porfa ayudenme con este ejercicio.

Daniel [21]

D) La camisa roja y el pantalon negro

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3 years ago

Read 2 more answers

Determine the greatest common factor of 15xy^7z and 30x^2y^7z

yawa3891 [41]

Answer:

$15x {y}^{7} z$

Step-by-step explanation:

<h3>Factorize the Expressions</h3>

$15x {y}^{2} z = 3 \times 5 \times x \times y \times y \times y \times y \times y \times y \times y \times z$

$30 {x}^{2} {y}^{7} z = 2 \times 3 \times 5 \times x \times x \times y \times y \times y \times y \times y \times y \times y \times z$

<h3>Factor out the Common Factors</h3>

$gcf = 3 \times 5 \times x \times y \times y \times y \times y \times y \times y \times y \times z$

<h3>Multiply the Common Factors</h3>

$3 \times 5 \times x \times y \times y \times y \times y \times y \times y \times y \times z = 15x {y}^{7} z$

The Factored expressions are

$15x {y}^{7} z$

And

$15x {y}^{7} (2x)$

5 0

3 years ago

Look at the picture down below and help me out?

d1i1m1o1n [39]

Is 20 and answer because I did this on a calculator and this is the only one to me that would make since

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2 years ago

12) You can exchange $5 US dollars for L123 Honduran Lempiras. How many dollars can you exchange L2,300 for? ----

Anit [1.1K]

Step-by-step explanation:

$5 US dollar = L123 Honduran Lempiras

L2300Honduran Lempiras = x ( Let $ be x)

By using chain rule, we get

5×2300 = 123×x

or, 11500 = 123x

or, x = 11500÷123

hence, x = 93.49593496

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1 year ago

1. The most massive planet in the solar system, Jupiter, has a mass of about 1,898,000,000,000,000,000,000,000,000 kg. Estimate

UNO [17]

Answer:

D. $2*10^{27} kg$

Step-by-step explanation:

Mass of Jupiter is given as 1,898,000,000,000,000,000,000,000,000 kg

Estimating this to the nearest whole number would be = 2,000,000,000,000,000,000,000,000,000 kg (rounding up the the "1,898")

To express this in scientific notation form, simply count how many zeros we have to the nearest whole number, 2.

We have 27 zeros there.

Therefore, we would multiply the whole number, 2, by 10 raise to the power of 27.

An estimate of the mass of Jupiter = $2*10^{27} kg$

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3 years ago